1-D wave resonance in the case of an Open-Ended String

Click For Summary
The discussion centers on the wave equation for an open-ended string, represented by the equation ∂²y/∂t² = v²∂²y/∂x². The general solution is given as y = A sin(kx + ωt) + B cos(kx + ωt). For a string fixed at both ends, the boundary conditions are y(0,t) = 0 and y(L,t) = 0. In the case of an open-ended string, the appropriate boundary condition is that the derivative of y with respect to x at the ends must equal zero, indicating a free end. This leads to the conclusion that both ends of a free string have the same boundary condition of ∂y/∂x = 0.
Another
Messages
104
Reaction score
5
Homework Statement
I want to know the conditions in the case of Open-End.
Relevant Equations
## \frac{1}{v^2} \frac{∂^2y}{{∂t}^2} = \frac{∂^2y}{{∂x}^2} ## and general solution ## y = A sin(kx+ωt)+ B cos(kx+ωt) ##
Last edited by a moderator:
Physics news on Phys.org
Try $$\left. \frac{\partial y}{\partial x} \right|_{x=L} =0.$$
 
  • Like
Likes Another
kuruman said:
Try $$\left. \frac{\partial y}{\partial x} \right|_{x=L} =0.$$
242686


if free string both ends. The condition is ##\left. \frac{\partial y}{\partial x} \right|_{x=L} =0.## and ## \left. \frac{\partial y}{\partial x} \right|_{x=0} =0.## ?
 
Another said:
View attachment 242686

if free string both ends. The condition is ##\left. \frac{\partial y}{\partial x} \right|_{x=L} =0.## and ## \left. \frac{\partial y}{\partial x} \right|_{x=0} =0.## ?
Yes.
 
  • Like
Likes Another
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K
Replies
8
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
13
Views
2K
Replies
17
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K