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WPCareyDevil
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[SOLVED] (101)Conservation of linear momentum
A 86.7 kg man is standing on a frictionless ice surface when he throws a 0.1 kg book at 11.2 m/s. With what speed does the man move across the ice as a result?
Since the momentum of the thrown book must equal that of the man in the opposite direction, m1v1=m2v2, or so I thought.
I solved for the momentum of the book (.1)(11.2)=1.12 and then set that equal to the man*v
So... 1.12=86.7v, v=.0723
But that's was incorrect. So, no credit on my webassign homework but I would still like to understand how to solve it. Can someone help me out?
Homework Statement
A 86.7 kg man is standing on a frictionless ice surface when he throws a 0.1 kg book at 11.2 m/s. With what speed does the man move across the ice as a result?
Homework Equations
Since the momentum of the thrown book must equal that of the man in the opposite direction, m1v1=m2v2, or so I thought.
The Attempt at a Solution
I solved for the momentum of the book (.1)(11.2)=1.12 and then set that equal to the man*v
So... 1.12=86.7v, v=.0723
But that's was incorrect. So, no credit on my webassign homework but I would still like to understand how to solve it. Can someone help me out?