[SOLVED] (101)Conservation of linear momentum 1. The problem statement, all variables and given/known data A 86.7 kg man is standing on a frictionless ice surface when he throws a 0.1 kg book at 11.2 m/s. With what speed does the man move across the ice as a result? 2. Relevant equations Since the momentum of the thrown book must equal that of the man in the opposite direction, m1v1=m2v2, or so I thought. 3. The attempt at a solution I solved for the momentum of the book (.1)(11.2)=1.12 and then set that equal to the man*v So... 1.12=86.7v, v=.0723 But thats was incorrect. So, no credit on my webassign homework but I would still like to understand how to solve it. Can someone help me out?