11th gr. chem (composition of a hydrate)

  • Thread starter Thread starter monica_e826
  • Start date Start date
  • Tags Tags
    Chem Gr
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 5K views
monica_e826
Messages
1
Reaction score
0
i might get confusing cause i don't understand this very much
but here is the copy of my lab i need help with #1 & 6 of the POST-ALAYSIS
here is the word doc. of my lab
http://courses.digitaldapp.org/documents/Inquiry Lab - Experiment 03 - Composition of a Hydrate.doc


btw.
5 grams of copper II sulfate was used
when it became an anyhride it had a mass of 0.15g


i know i made a mistake somewhere in my lab and i was wondering if you tell where my mistake is and what i should do. i would highly appreciate it.

so i know...
CuSO4 . 5H2O
molar weight is 249.69g


by itself is
CuSO4 = 159.61g
5H2O= 90.81

so i took the
mass of the water/total mass of hydrate x100= 36% of H2O removed in anhydrous copper (II) sulfate.

am i correct?
this is where i got confused...
-determine the # of moles of water present in each mole of hydrous copper (II) sulfate.
so what i did was:
5H2O

H10= 11%=11/1.0079=10.91=2
O5=88%=88/15.9994=5.5=1
is this the correct Empirical formula?
2H10O5 & can be simplified to 2H2O

so now what do i use to find the amount of moles of water present?
 
Physics news on Phys.org
monica_e826 said:
i might get confusing cause i don't understand this very much
but here is the copy of my lab i need help with #1 & 6 of the POST-ALAYSIS
here is the word doc. of my lab
http://courses.digitaldapp.org/documents/Inquiry Lab - Experiment 03 - Composition of a Hydrate.doc


btw.
5 grams of copper II sulfate was used
when it became an anyhride it had a mass of 0.15g

Are you sure you got that right? I assume that "it had a mass of..." means that the anhydride had a mass of... Is that right?


i know i made a mistake somewhere in my lab and i was wondering if you tell where my mistake is and what i should do. i would highly appreciate it.

so i know...
CuSO4 . 5H2O
molar weight is 249.69g


by itself is
CuSO4 = 159.61g
5H2O= 90.81

Good so far...

so i took the
mass of the water/total mass of hydrate x100= 36% of H2O removed in anhydrous copper (II) sulfate.

am i correct?
this is where i got confused...
-determine the # of moles of water present in each mole of hydrous copper (II) sulfate.
Here is where you strayed off course. The formula for your unknown hydrate is CuSO4 . XH2O. You need to solve for 'X', not assume that it is 5 and do some math without using any of the data you collected.

Show us the raw data you collected.