How Long Should Nancy Invest to Save $5000?

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Homework Help Overview

The discussion revolves around a problem in finance, specifically regarding compound interest and investment duration. The original poster seeks to determine how long Nancy should invest $4000 at a 9.75% annual interest rate, compounded semiannually, in order to reach a savings goal of $5000.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore different equations for compound interest, including variations of the formula and the implications of semiannual compounding. Questions arise regarding the setup of the equations and the interpretation of the interest rate.

Discussion Status

Participants have provided various equations and interpretations of the problem. Some have suggested specific calculations, while others have questioned the assumptions made in the setup. There is an ongoing exploration of how to accurately represent the compounding effect in the equations.

Contextual Notes

There is a focus on the semiannual compounding aspect of the interest rate, which influences the calculations. Participants are also navigating the implications of rounding in their results.

mcbates
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i am having problems figuring out how to find the answer to this problem:

nancy wants to invest $4000 in saving certificates that bear an interest rate of 9.75% per yr, compound semiannually. how long a time period should she choose inorder to save an amt of $5000?

the answer is approximately 2.3 yrs. i am not sure how to get this answer. pleasssseee help!
 
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What have you tried?
Do you know how to set up the equation somewhat?
 
i think you use the equation Ao(1+r/n)^nt: i think this one is it.
or Ao e^rt (growth)
 
Well, we have 4000 at the start and it increased by 9.75 percent, which we can express by multiplying with 1.0975, this for each year. We also know what we want to end up with, so we get the equation: 4000 \cdot 1.0975^n = 5000

Here, n is the number of years. Now, could you solve it?
 
Last edited:
how does that end up being 2.3 years
 
mcbates said:
how does that end up being 2.3 years
n = \frac{ln(\frac{5000}{4000})}{ln(1,0975)}
 
Indeed, and that's approximately 2.39 (so I'd say 2.4 when rounding...)
Since the interest comes semianually, to get (at least) the 5000 you have to wait 2.5 years.
 
where did you get 1.0975 from?
 
Didn't you read post #4? I already included the equation for you :smile:
 
  • #10
okayyyy! Thanks! :smile:
 
  • #11
No problem :smile:

But since you didn't set it up yourself, I hope you do understand it?
If not, don't hesitate to ask for further details!
 
  • #12
the only reason i was wondering was because if you set it up in the equation i gave you it would be (1+9.75/2)^2T,,,i think
 
  • #13
Well I don't fully understand that one, where did you get the "2" for n?
 
  • #14
because the rate of interest in compounded semiannually
 
  • #15
Then, I think, the equation should be:

4000\left( {1 + \frac{{0.0975}}<br /> {2}} \right)^{2t} = 5000

That gives approx 2.34

I assume this is correct, because in my earlier equation we didn't use the fact that the interest was semianually.
 

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