- #1
RedBurns
- 24
- 2
Could someone please help me in determine the correct formula(s) to answer this problem?
A helicopter is ascending vertically with a speed of 2.50 m/s. At a height of 120 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground?
I know:
Acceleration -9.8 m/s/s
Initial position 120m
Final postion 0m
velocity 2.50m/s
I need to determine time.
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Would 2.50/-9.8 give me the correct time of .26 seconds or have I missed something here?
or would I use 0=120 + 2.50T + .5(-9.8)T^2 giving the time of 50 seconds?
A helicopter is ascending vertically with a speed of 2.50 m/s. At a height of 120 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground?
I know:
Acceleration -9.8 m/s/s
Initial position 120m
Final postion 0m
velocity 2.50m/s
I need to determine time.
------------------------------------------
Would 2.50/-9.8 give me the correct time of .26 seconds or have I missed something here?
or would I use 0=120 + 2.50T + .5(-9.8)T^2 giving the time of 50 seconds?
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