MHB 2.2.212 AP Calculus Exam problem find increasing interval

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The function f(x) = 300x - x^3 is analyzed for increasing intervals. The critical points are found at x = -10 and x = 10, where the slope is zero, indicating potential endpoints. The consensus is that the function is increasing on the interval (-10, 10), as the endpoints cannot be included due to the slope being zero at those points. However, there is a debate regarding whether the closed interval is acceptable according to AP guidelines. Ultimately, the correct interpretation hinges on the definition of increasing functions as used in AP calculus.
karush
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Let f be the function given by $f(x)=300x-x^3$ On which of the following intervals is the function f increasing
(A) $\quad (-\infty,-10]\cup [10,\infty)$

(B) $\quad [-10,10]$

(C) $\quad [0,10]$ only

(D) $\quad [0,10\sqrt{3}]$ only

(E) $\quad [0,\infty]$
Steps
find first derivative to find min/max
$$y'=300-3x^2=3(100-x^2)=3(10+x)(10-x)$$
hence where $y'=0$ is at $-10,10$
an increasing interval of graph would have an positive slope so where
$$y'(0)=300$$
which is positive so the interval
$$[-10,10]\quad (B)$$

ok this was a little awkward to explain provided the answer is correct
but it was easy to get the zeros wrong due the highest power was the last term
 
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karush said:
212
Let f be the function given by $f(x)=300x-x^3$ On which of the following intervals is the function f increasing
(A) $\quad (-\infty,-10]\cup [10,\infty)$

(B) $\quad [-10,10]$

(C) $\quad [0,10]$ only

(D) $\quad [0,10\sqrt{3}]$ only

(E) $\quad [0,\infty]$
Steps
find first derivative to find min/max
$$y'=300-3x^2=3(100-x^2)=3(10+x)(10-x)$$
hence where $y'=0$ is at $-10,10$
an increasing interval of graph would have an positive slope so where
$$y'(0)=300$$
which is positive so the interval
$$[-10,10]\quad (B)$$

ok this was a little awkward to explain provided the answer is correct
but it was easy to get the zeros wrong due the highest power was the last term
It looks good, but there is an error: the answer key doesn't have a correct answer!

Your analysis is good except at the endpoints. The slope of the function is 0 at the points x = -10 and x = 10. Since 0 is neither positive nor negative the endpoints cannot be part of your answer. The correct answer is (-10, 10).

-Dan
 
topsquark said:
It looks good, but there is an error: the answer key doesn't have a correct answer!

Your analysis is good except at the endpoints. The slope of the function is 0 at the points x = -10 and x = 10. Since 0 is neither positive nor negative the endpoints cannot be part of your answer. The correct answer is (-10, 10).

-Dan

according to the definition of an increasing function used by the AP folks, the closed interval is correct ...

https://teachingcalculus.com/2012/11/02/open-or-closed/