2 black holes, 2*M -> 1 b.h., 2*M - f*2*M?

  • Level: Graduate 
  • Thread starter Thread starter Spinnor
  • Start date Start date
  • Tags Tags
    Black holes Holes
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 2K views
Spinnor
Gold Member
Messages
2,234
Reaction score
419
2 black holes, 2*M --> 1 b.h., 2*M - f*2*M?

For equal sized black holes of mass M, what fraction, f, of the energy typically gets lost as gravitational radiation when roughly equal sized black holes merge?

If f were plotted verses mass would the function have a maximum?

Thanks for any help!
 
Physics news on Phys.org


For starting point, try page 4 of

http://arxiv.org/abs/0708.4202
Gravitational waves from black-hole mergers
John G. Baker, William D. Boggs, Joan M. Centrella, Bernard J. Kelly, Sean T. McWilliams, James R. van Meter
 


For two identical static black holes, the rigorous theoretical upper limit is the Hawking bound of (2-√2)m (eg 29% of the initial total mass). Numerical simulations typically show much lower amounts of radiation on the order of 0.1..4% (and up to 14% in the scattering regime).
 
Last edited:


atyy said:
For starting point, try page 4 of

http://arxiv.org/abs/0708.4202
Gravitational waves from black-hole mergers
John G. Baker, William D. Boggs, Joan M. Centrella, Bernard J. Kelly, Sean T. McWilliams, James R. van Meter

If I follow the paper above, for star sized black holes the fraction lost is about 1/20 the mass of the initial black hole pair. Are there any simple arguments one could give to explain how this fraction changes (or does not change) with black hole mass.

Thanks for your help!