2 blocks collide, 5% energy loss. 2 answers, which correct?

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Homework Help Overview

The discussion revolves around a collision problem involving two blocks, Block A and Block B, with specified masses and initial velocities. The problem includes a 5% energy loss during the collision, and participants are exploring how to determine the correct final velocities of the blocks after the collision.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the final velocities obtained from a quadratic equation and question how to ascertain which set of velocities is correct given the energy loss. There is consideration of the physical implications of the larger block moving faster than the smaller block after the collision.

Discussion Status

The discussion is ongoing, with participants sharing insights about the physical constraints of the problem. Some express confusion about the implications of the calculated velocities, while others suggest that the larger block cannot move faster than the smaller block after the collision, indicating a need for further exploration of the results.

Contextual Notes

Participants note that the larger block must be moving slower than the smaller block after the collision due to their relative positions, which raises questions about the validity of the computed velocities. There is also mention of a scenario where no energy loss results in a different outcome, suggesting that the energy loss alters the expected results significantly.

Ocata
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Homework Statement

The question I have is not how to arrive at the correct values of final velocity, but once I have the values of final velocity, how do I know which velocities (which are computed from a quadratic equation) are correct?

Two blocks, block A and Block B, are traveling to the right.

Before collision:

Block A is 4kg at 10m/s
Block B is 2kg at 5m/s

After collision:

Block A is 4kg at vf = ?
Block B is 2kg at Vf = ?

Energy loss is .05

Homework Equations

mvi + MVi = mvf + MVf

1/2mvf^2 + 1/2MVf^2 = .95[1/2mvi^2 + 1/2MVi^2]

The Attempt at a Solution



mvi + MVi = mvf + MVf ==> Vf = 25 - 2vf

1/2mvf^2 + 1/2MVf^2 = .95[1/2mvi^2 + 1/2MVi^2] ==> 4vf^2 + 2Vf^2 = 427.54vf^2 + 2(25 - 2vf) = 427.5 ==> 12vf^2 - 200vf + 822.5 = 0

Quadratic Formula ==> vf = 9.28m/s and 7.38m/s

then,
Vf = 25 - 2(9.28) = 6.44m/s and Vf = 25 - 2(7.38) = 10.24m/s

So the possible answers are:

[vf = 9.28m/s Vf = 6.44m/s] or [vf = 7.38m/s Vf = 10.24]


Given the energy loss of .05, how could I know which set of final velocities are correct? I don't think I can just rationalize it because in either case, the faster, heavier block A slows down upon colliding with the lighter, slower block B. And Block B speeds up upon being struck by the faster, heavier block A. What I mean is, in both final answers, Block A is slowing down and Block B is speeding up.

Is there a computation that will determine which set of velocities are correct?
 
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Ocata said:
So the possible answers are:

[vf = 9.28m/s Vf = 6.44m/s] or [vf = 7.38m/s Vf = 10.24]

Is there a computation that will determine which set of velocities are correct?

In the first case the larger block is moving faster than the smaller block after the collision. Do you think this is possible?
 
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Makes perfect sense PeroK. The larger block must be moving slower that the smaller block after collision because the larger block is behind the smaller block. It can't physically pass the smaller block. I was simply looking at the numbers in a scalar sense and not considering the bigger picture.

Thank you.
 
Ocata said:
Makes perfect sense PeroK. The larger block must be moving slower that the smaller block after collision because the larger block is behind the smaller block. It can't physically pass the smaller block. I was simply looking at the numbers in a scalar sense and not considering the bigger picture.

Thank you.

If you solve the problem with no energy loss, you'll find one solution is where the blocks miss each other and continue with their original velocities. The first case is, therefore, a variation of this with the 5% energy loss.
 
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Thanks PeroK
 

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