1. The problem statement, all variables and given/known data So here is the problem, There is a .03kg block that is in an inverted cone, the cone has a slant length of 15 cm and a radius of 4 cm, and the coefficient of friction is .35. The block rotates around the inside of the cone, seamlessly, until it hits the bottom of the cone. That is all we are given and we are supposed to find the final velocity of the block right before it hits the bottom of the cone. The picture attached is accurate except imagine that the cone is 3d and the block is moving in a circular motion around the edges of the cone. I have tried this numerous ways and each time I get an irrational answer. 2. Relevant equations Ff= (mu)(mg)(costheta) Vf^2= Vo^2 + 2a(X-Xo) Vf= Vo +at 3. The attempt at a solution I found the velocity of the block were it simply sliding down an inclined plane, pretty easy stuff, and I got 1.601 m/s for the final velocity. Its the centripetal/tangential acceleration that I'm having trouble with. What I did was I found what I think the tangential acceleration of the block using (mu)(Normal Force)/mass. If I did that correctly, I found the tangential acceleration to be .915 m/s^2. From there I used the kinematics equation vf= vo + at to find the final velocity. I found t from the equation t= √((2y)/a) using the height of the cone, .1446 cm, for y and .915 for a, and I found t to be .5621 seconds. So back to the kinematics equation vf= vo + at, I plugged in values and found vf= 0 + (.915)(.5621)= .514 m/s. So what I did from there was I plugged in the tangential final velocity and the final velocity of the block if it were down an inclined plane and plugged them into √((a)^2 + (b)^2)= √((1.601)^2 + (.514)^2) and got 1.68 m/s for the final velocity of the block, but I have no idea if that is correct. The picture below is accurate except imagine that the cone is 3d and the block is rotating around the inside of the cone.