Solve 2 Calculus Problems: Find Point & Write Equation

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SUMMARY

This discussion addresses two calculus problems related to finding points on a line and writing equations for shifted graphs. The first problem involves determining the point on the line defined by the points (1,-2) and (-3,1), with the correct answer being (5,-5). The second problem requires writing the equation for the graph of y=2x-5 shifted three units to the left, resulting in the equation y=2x+1. The transformation for shifting a function is clarified as f(x) -> f(x+3).

PREREQUISITES
  • Understanding of linear equations and points in a Cartesian plane.
  • Knowledge of function transformations, specifically horizontal shifts.
  • Familiarity with the concept of slope and intercepts in linear equations.
  • Basic skills in plotting graphs and interpreting their equations.
NEXT STEPS
  • Study the derivation of linear equations from two points using the slope-intercept form.
  • Learn about function transformations, focusing on horizontal and vertical shifts.
  • Practice problems involving shifting graphs of linear functions.
  • Explore the relationship between points on a line and their corresponding equations.
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Students preparing for calculus exams, educators teaching calculus concepts, and anyone interested in understanding linear equations and function transformations.

vee123
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I have two Calculus problems I need explained because I'm studying for a final exam and I forgot how to do these things:

#1: Find the point that lies on the line determined by the points (1,-2) and (-3,1).

The answer is (5,-5), but I don't know why...


#2: Write an equation satisfied by the graph obtained by shifting y=2x-5 three units to the left.

The answer is y=2x+1

I know when an equation is shown moving to the left, it is put in parentheses and a number is added to it (for example y=x^2 becomes y=(x^2+2) when it is moved two places to the left). However, I do not know how to do this problem.

Could someone please help me?
 
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vee123 said:
I have two Calculus problems I need explained because I'm studying for a final exam and I forgot how to do these things:

#1: Find the point that lies on the line determined by the points (1,-2) and (-3,1).

The answer is (5,-5), but I don't know why...


#2: Write an equation satisfied by the graph obtained by shifting y=2x-5 three units to the left.

The answer is y=2x+1

I know when an equation is shown moving to the left, it is put in parentheses and a number is added to it (for example y=x^2 becomes y=(x^2+2) when it is moved two places to the left). However, I do not know how to do this problem.

Could someone please help me?

Several things you can do. First off, these aren't calc questions, afaik.

1. Can you write down the equation determined by the two points? If so, then I guess you have choices to plug into the equation to see if they work.

2. The easiest thing to do is to just plot the thing and move it 3 units to the left, and see what you get. But you can also just apply some transforms. In your case, you can shift your function to the left ( f(x) -> f(x+3) ) by applying that transform.

See what you get :)
 
Thanks for the reply! I think I'm starting to remember this...

Yeah I know these aren't really calc questions, but they were in the beginning section of my calc. book.

Thanks for your help!
 
Anytime :D
 
Okay, I'm still having trouble with the second question. I know I may sound really stupid, but I tried to solve it by doing f(x)=(2x-5+3), and did not get the correct answer. What am I doing incorrectly?
 
Consider rewriting f(x) = 2x-5 as f(x) = 2(x-5/2).. and see if you get anything from there...
 
Now I understand! I was having a bit of a mental block at hte moment... Thank you very much! :)
 

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