2 derivations using the Conservation of Linear Momentum

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Homework Help Overview

The discussion revolves around deriving two equations related to conservation of linear momentum in a collision scenario involving two objects. The original poster presents two equations and seeks to derive additional relationships from them, focusing on the manipulation of trigonometric identities and algebraic expressions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to square both sides of the equations and apply trigonometric identities. There is a suggestion to work backwards from the desired result, particularly focusing on the cosine of the sum of angles.

Discussion Status

The conversation includes attempts to clarify the context of the problem, with some participants confirming the nature of the collision and questioning the setup of the equations. There is an indication that hints and guidance have been provided, particularly regarding the application of trigonometric identities.

Contextual Notes

Participants note potential confusion regarding the nature of the event (collision vs. explosion) and the implications of mass in the equations. There is also a question about the correctness of notation in the equations presented.

auk411
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Homework Statement



I have 2 equations. I need to derive two different equations from them.

Derive (1): v102= v1f2 + vf22+ 2v1fv2fcos(φ+θ)

(2): v2f = v10sin[tex]\theta[/tex]/sin(theta - phi)

Homework Equations



v10= v1fcosθ + v2fcosφ
0 = v2fsinφ - v2fsinθ

The Attempt at a Solution



I know for one you are going to have to square both sides of both equations. I figure I'm going to have to use some trig identities (actually for both), but I can't seem to find anywhere to go.

These are part of larger problems that I have worked through and set up but I can't seem to do the algebra/trig.
 
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auk411 said:

Homework Equations



v10= v1fcosθ + v2fcosφ
0 = v2fsinφ - v2fsinθ

It look like you're considering the case of an object that is traveling entirely in the horizontal direction when it suddenly "explodes" into two pieces, one of which moves off at an angle of theta above the horizontal, and the other of which travels off at an angle of phi below the horizontal. Am I right? The relevant equations you have posted then come from conservation of momentum in the horizontal and vertical directions respectively. Correct? (EDIT: Hmm...but what about the masses? :confused:)

EDIT 2: No, I figured it out. It wasn't an explosion. It was a collision. Mass 1 one traveling horizontally when it collided with *stationary* object 2 of EQUAL mass, which is why the masses cancel from both sides. They then traveled off obliquely, right?

Also, should the '2' in red actually be a '1'?
 
Last edited:
auk411 said:
I know for one you are going to have to square both sides of both equations. I figure I'm going to have to use some trig identities (actually for both), but I can't seem to find anywhere to go.

Yeah. Have you done that (squared both sides?) What did you get? Can you see how might manipulate that to turn it into the result?

Here's another hint: work backwards from the result. It has cos(φ+θ) in it. There are some trigonometric identities known as the "sum and difference formulae" that tell you what the sine and cosine of a sum or difference of two angles is. Applying that to the result, what do you get?
 
cepheid said:
Yeah. Have you done that (squared both sides?) What did you get? Can you see how might manipulate that to turn it into the result?

Here's another hint: work backwards from the result. It has cos(φ+θ) in it. There are some trigonometric identities known as the "sum and difference formulae" that tell you what the sine and cosine of a sum or difference of two angles is. Applying that to the result, what do you get?

Thanks, I got it.
 

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