- #36

NTesla

- 143

- 21

I'm trying to understand your calculation in post #4. You have taken ##x_1,x_2## as coordinates.You have done the calculation so know that ##l## is constant. So your ##l##=##x_2-x_1## means spring between block 1 and block 2 does not change its length like a rod, though the equation is that of harmonic oscillation. Do I catch you right ?

##l## is the length of string at any instant of time. It is not a constant. ##l## changes wrt time.

##l##=##x_2-x_1##, considering that ##x_1, x_2## are coordinates of the masses ##m_1## and ##m_2##.

But, the value of ##x_2-x_1-l=0## always.

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