2 Vectors with Angles acting on an object

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SUMMARY

The discussion focuses on calculating the net force acting on an object influenced by two vectors, F1 and F2. F1 is 12 N at an angle of 32 degrees upwards, while F2 is 15 N at an angle of 24 degrees downwards. The net force in the x-direction (Fnetx) is calculated as 23.87 N, and in the y-direction (Fnety) as 0.26 N. To find the resultant force (Fnet), the Pythagorean theorem is applied, yielding a magnitude of 23.87 N, and the angle is determined using trigonometric ratios, resulting in an angle of approximately 0.62 degrees.

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JackandJones
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Hey guys, I am having a little trouble determining the final answer to this question.

Basically an object is being pulled by two forces and I am suppose to find the Net Force

F1 = 12 N at an angle of 32 degrees (upwards)
F2 = 15 N at an angle of 24 degrees (downwards)

So what I did was split the two vectors and try to find Fnetx and Fnet y

For Fnetx = F1net + F2net

F1 = 12Cos(32)
F2 = 15 cos(24)

I added F1x and F2y and got
Fnetx = 23.87 N

For Fnety

F1y = 12sin32 = 6.36 N
F2y = 15sin24 = 6.10 N

I subtracted F1y-F2y because F2y is going in the negative direction so
Fnety = 0.26 N

I am not sure if I should add these together or use PT to get Fnet...then use Trig ratios to get the angle... ?

Any ideas? I appreciate the help!
 
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You've now got the x and y components of a vector.
So how do you calculate the length and direction of the vector from them?

(You can't just add the lengths of the components - that would make no sense.)
 
AJ Bentley said:
You've now got the x and y components of a vector.
So how do you calculate the length and direction of the vector from them?

(You can't just add the lengths of the components - that would make no sense.)

If I have Fnetx and Fnety

Would I use pythegorean theorem to find Fnet, and then Trig ratio to get the angle?
 
Exactly that.
 
Nytik said:
Exactly that.


Okay perfect However could you please explain why I would not substract the F1y by the F2y?

Because F2y is a downward motion, it would not be negative?
 
You do subtract them; everything you have done up to this point is correct.
 
Nytik said:
You do subtract them; everything you have done up to this point is correct.

Okay its just that the answer doesn't seem correct to me.

Fnetx = 23.87 N

Fnety = 0.26 N

Using PT:

Fnet = 23.87 N

Then then using Trig Ratios, the Angle = 0.62 degrees... which doesn't seem correct..?
 
This thread has been moved to the "Introductory Physics" section of "Homework & Coursework Questions", where it should have been posted in the first place. Carry on, and try to remember to post similar questions here in the future. :smile:
 

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