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RjD12

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## Homework Statement

Mortar crew is near the top of a steep hill. They have a mortar. They angle this mortar at an angle of [itex]\theta[/itex] = 65° . The crew fires a shell at a muzzle velocity of 228 ft/sec (69.5 m/s). How far down the hill does the shell strike if the hill subtends an angle of [itex]\phi[/itex] = 32° from the horizontal?

How long will the mortar remain in the air?

How fast will the shell be traveling when it hits the ground?

Relevant diagram: http://imgur.com/apimguh

## Homework Equations

Kinematic Equations:

X= X

_{o}+ V

_{ox}t

Y= Y

_{o}+ V

_{oy}t - (1/2)at

^{2}

## The Attempt at a Solution

First off, I'm not expecting to get all of my questions answered. I just need a little push.

I'm not sure where to start off at here. The fact that there are two angles here confuses me in regards to how they work in the equations.

I can say that V

_{ox}= 69.5cos(65) and that V

_{oy}= 69.5sin(65).

I'm really thrown off by the way the angles work here, and whether the distance works with a simple range equation. Any tips on where to start?

edit: Additionally, I was given the equation

*d = V*as a hint for this. Isn't this wrong though, seeing as how the velocity should be multiplied with time?

_{o}+ (1/2)at^{2}
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