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## Homework Statement

A daredevil is shot out of a cannon at 33.7◦ to the horizontal with an initial speed of 25.5 m/s. A net is positioned at a horizontal distance of 43.7 m from the cannon from which the daredevil is shot.

The acceleration of gravity is 9.81 m/s^2

At what height above the cannon’s mouth should the net be placed in order to catch the daredevil?

Answer in units of m

Given: θ = 33.7; vo = 25.5 m/s; dx = 43.7m; a = 9.81m/s^2

Find: dy

## Homework Equations

vox = vo(cosθ)

voy = vo(sinθ)

[I'm stuck on what other equations I can use]

## The Attempt at a Solution

I first drew a diagram with no problem.

vox = (25.5m/s)cos33.7 = 21.1m/s @ a = 0m/s^2

voy = (25.5m/2)sin33.7 = 14.1m/s @ a = -9.81m/s^2

So we now know initial velocity in the x direction is 21.1m/s, and initial velocity in the y direction is 14.1m/s. I am a little confused on where to go from here.