2D - Momentum Question, Grade 12 Canadian Physics

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SUMMARY

The discussion focuses on a physics problem involving an inelastic collision between two cars with masses of 1,400 kg and 1,300 kg, traveling at velocities of 45 km/h south and 39 km/h east, respectively. The correct post-collision velocity is determined to be 30 km/h at an angle of 51 degrees south of east. The conservation of momentum principle is applied, confirming that total momentum is conserved rather than total velocity. A vector diagram is essential for visualizing the momentum before and after the collision.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Knowledge of vector addition and decomposition
  • Familiarity with inelastic collisions in physics
  • Ability to create and interpret vector diagrams
NEXT STEPS
  • Study the conservation of momentum in inelastic collisions
  • Learn how to construct vector diagrams for collision problems
  • Explore the mathematical derivation of angles in vector triangles
  • Practice additional problems involving two-dimensional momentum analysis
USEFUL FOR

High school physics students, educators teaching mechanics, and anyone preparing for physics exams focused on momentum and collisions.

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Homework Statement


2 cars collide at an intersection.
one car which has a mass of 1,400kg has a velocity of 45 km/h;
the other car has a mass of 1,300kg and has a velocity of 39 km/h[E]
The cars has an inelastic collision. What are their velocity after the collision


Homework Equations



Conservation of momentum: P total = P total prime


The Attempt at a Solution



I have tried on numerous occasions but have not achieved the correct answer.

The correct answer should be: "30 km/h [ 51 South of East.]

I got the correct magnitude of the velocity which is 30 km/h. Easy enough, but i didn't get the degrees required. Additional vector diagram is appreciated.
 
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Try to draw the vector diagram for the initial total momentum of the system.
 
@grzz I figured out what i did wrong. When i calculated for the theta of the vector triangle. I simply used the velocities. Instead i tried it with m(v) and it worked for me. Thanks.
 
You just confirmed that it is the total momentum that is conserved and not the total velocity!
 

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