3 concentric conducting spheres, the outer one connected to ground

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SUMMARY

The discussion centers on the implications of connecting the outer surface of three concentric conducting spheres to ground, specifically regarding the electric potential and charge density. It establishes that the potential at the outer surface, V(r=R_5), equals zero due to grounding. The conversation also highlights the relationship between surface charge densities, particularly between σ_1 and σ_2, and the electric field outside R_5, which influences σ_5. Relevant equations include Gauss's law, expressed as ∮ E·dS = q/ε₀.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with Gauss's law and its applications
  • Knowledge of charge density concepts (σ_i)
  • Basic principles of potential difference in electrical systems
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  • Study the implications of grounding in electrostatic systems
  • Learn about the derivation and application of Gauss's law in complex geometries
  • Investigate the relationship between electric field and charge density in conductors
  • Explore potential theory in electrostatics, focusing on spherical conductors
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Students and professionals in physics, electrical engineering, and anyone studying electrostatics, particularly those interested in the behavior of conducting spheres and grounding effects.

Sokolov
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Homework Statement
Three concentric conductor spheres, the outer of them connected to ground, have electrical charges[itex]Q_A[/itex], [itex]Q_B[/itex] and [itex]Q_C[/itex], and radii[itex]R_1[/itex], [itex]R_2[/itex], [itex]R_3[/itex], [itex]R_4[/itex] and[itex]R_5[/itex], from the inner to the outer. Find the induced charges and the equations of the electric field and the potential of the system.
Relevant Equations
[tex] \oint \vec E\cdot d\vec S =\frac{q}{\epsilon_0}[/tex]
Esferas.png

What would the fact that the fifth surface is connected to the ground imply: that V(r=R_5)=0 or that \sigma _5=0?
 
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Hello Sokolov, :welcome: !

Ground is considered ##V=0##.
Perhaps not extremely interesting for part two, since ##E## is a derivative.
 
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Sokolov said:
Homework Statement:: Three concentric conductor spheres, the outer of them connected to ground, have electrical chargesQ_A, Q_B and Q_C, and radiiR_1, R_2, R_3, R_4 andR_5, from the inner to the outer. Find the induced charges and the equations of the electric field and the potential of the system.
Relevant Equations:: \oint \vec E\cdot d\vec S =\frac{q}{\epsilon_0}

View attachment 258000
What would the fact that the fifth surface is connected to the ground imply: that V(r=R_5)=0 or that \sigma _5=0?
Couple of hints to add to BvU's:
1. what can you say about ##\sigma_2 ## vs. ##\sigma_1 ##? Etc?
2. What must be the field outside R5? What does that imply for ## \sigma_5 ## assuming you've worked out the other sigmas?

P.S. ## \sigma_i ## means charge density on surface i.
 
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BvU said:
Hello Sokolov, :welcome: !

Ground is considered ##V=0##.
Perhaps not extremely interesting for part two, since ##E## is a derivative.

Hi BvU, thanks for the answer! It was just what I needed to know in order to be able to solve the problem.
 
rude man said:
Couple of hints to add to BvU's:
1. what can you say about ##\sigma_2 ## vs. ##\sigma_1 ##? Etc?
2. What must be the field outside R5? What does that imply for ## \sigma_5 ## assuming you've worked out the other sigmas?

P.S. ## \sigma_i ## means charge density on surface i.

Thanks rude man! With your hints and BvU's answer I think that I have been able to solve the problem correctly :) .
 

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