3 excess electrons calculate the radius

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SUMMARY

This discussion focuses on calculating the radius of an oil droplet with three excess electrons in an electric field of 4.24 x 104 N/C. The solution involves applying the equation F = qE = mg, where the mass is derived from the density (824 kg/m3) and volume of the droplet, assumed to be spherical. The calculated radius is 8.43 x 10-7 m. Additionally, the discussion addresses the charge densities on a coaxial cable, concluding that the correct linear charge densities on the inner and outer conductors are -10 nC/m and -30 nC/m, respectively.

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3 excess electrons...calculate the radius...coaxial cable...

Homework Statement


An oil droplet with 3 excess electrons is held stationary in a field of 4.24x104N/C.
What is the radius of the oil drop?( The density of the oil is 824 kg/m3,e=1.60x10-19C)

Homework Equations


F=qE=mg
m=(density)(volume)

The Attempt at a Solution


well i assumed that the droplet was a sphere and so the volume would be (4/3 [tex]\pi[/tex]r3. So i set F=qe=mg because the droplet is stationary so the net force is zero. And the mass = density x volume so i just plugged every thing in and solved for r ...i got 8.43 x 10-7...can some one verify this ..i am not really confident lol

Homework Statement


The cross section of a long coaxial cable is shown, with radii as given. The linear charge density on the inner conductor is-10nC/m and the linear charge density on the outer is -40nC/m. The inner and outer cylindrical surfaces are respectively denoted A,B,C and,D ad shown. The linear charge densities on surfaces C and D, in nC/m, are closest to:
A) +10 and -40
B) -10 and -30
C) 0 and -40
D) +10 and -50
E) -30 and -10

22.6.jpg


Homework Equations


I'm not exactly sure what to do...

The Attempt at a Solution


The only thing i could think of was that the system is a conductor so the inside charges must be equal to zero and so i thought that what ever the inside charges added up to then the outside charge would be the same magnitude as the sum of the inside charges but opposite in sign. I don;t even know if that is conceptually correct ...please help ...i don;t think i understand the underlying concept of this question...let alone actually solving it haha.
 
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The correct answer is B) -10 and -30. The charge density of the inner conductor is -10 nC/m, and the charge density of the outer conductor is -40 nC/m. Since the system is a conductor, the total charge on the inner conductor and the total charge on the outer conductor must be equal and opposite. Therefore, the charge density on the outer conductor must be -10 nC/m + (-40 nC/m) = -50 nC/m. This means that the charge density on the inner conductor must be -30 nC/m.
 

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