3 printers rest on top of each other on a table [FORCES]

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Homework Help Overview

The problem involves three printers stacked on top of each other, with the goal of determining the forces exerted by the middle printer on the top and bottom printers. The weights of the printers are given, and the context is rooted in the principles of forces and equilibrium.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of forces between the printers, with one suggesting to treat the top two printers as a single unit to find the force on the bottom printer. There is also questioning about the validity of combining objects in calculations and the implications for equilibrium.

Discussion Status

The discussion is ongoing, with participants providing insights into the calculations and questioning the assumptions made about the forces involved. Some guidance has been offered regarding the need for balanced forces, but there is no explicit consensus on the correct approach yet.

Contextual Notes

Participants note the importance of equilibrium in the problem and express uncertainty about the appropriateness of combining the weights of the printers in their calculations. There is also a suggestion to consider a simpler problem for clarity.

dungas
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Homework Statement


Three printers [X, Y, Z] are placed on top of each other on a table. What force does the middle printer exert on each of the other two printers.

x is on top, y in middle, and z on bottom.

x = 4 kg, y = 3 kg , and z = 2 kg
2. F = ma



The Attempt at a Solution



I can consider the top two printers as one so the weight would be 7 kg.

F = (7kg)(9.8 m/s^2 )
= 68.6 N

That would be the force exerted on z(the bottom printer).

The normal force would be exerted on the top printer so:

F = (5kg)(9.8 m/s^2 )
= 49 N

However this doesn't make sense since, the objects are in equilibrium so they're suppose to be equal...Please help?
 
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68.6 N is the force between the middle and the lower printer, and required to support the upper two printers.
You can use the same argument to calculate the force between the upper and the middle printer - you can even save one step, as you don't have to combine objects there.
 
mfb said:
68.6 N is the force between the middle and the lower printer, and required to support the upper two printers.
You can use the same argument to calculate the force between the upper and the middle printer - you can even save one step, as you don't have to combine objects there.

The forces have to balance out so would be just 68.6 between the middle one and the upper one.

Also, since I'm combining objects in my previous calculations. wouldn't it be incorrect because I'm taking into account the forces of two objects when I should be just finding the force exerted by the middle one(y). The thought just came in my mind.
 
dungas said:
The forces have to balance out so would be just 68.6 between the middle one and the upper one.
This would not give balanced forces, as you have nothing to balance the gravitational force of the middle printer then.

Also, since I'm combining objects in my previous calculations. wouldn't it be incorrect because I'm taking into account the forces of two objects when I should be just finding the force exerted by the middle one(y). The thought just came in my mind.
I don't understand what you mean.

Try to solve an easier problem first: Two printers, standing on a table. The upper one has a mass of 4kg, the lower one has a mass of 3kg. What is the force between them? Does this give balanced forces on the upper printer?
 

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