1. The problem statement, all variables and given/known data Three printers [X, Y, Z] are placed on top of each other on a table. What force does the middle printer exert on each of the other two printers. x is on top, y in middle, and z on bottom. x = 4 kg, y = 3 kg , and z = 2 kg 2. F = ma 3. The attempt at a solution I can consider the top two printers as one so the weight would be 7 kg. F = (7kg)(9.8 m/s^2 ) = 68.6 N That would be the force exerted on z(the bottom printer). The normal force would be exerted on the top printer so: F = (5kg)(9.8 m/s^2 ) = 49 N However this doesn't make sense since, the objects are in equilibrium so they're suppose to be equal...Please help?