3 Questions regarding reaction kinetics- me out.

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SUMMARY

This discussion focuses on the principles of reaction kinetics, specifically the definition of reaction rates and their applicability across different types of reactions. The equation for reaction rates, represented as -(1/a)*(d[A]/dt)= -(1/b)*(d[B]/dt) = -(1/p)*(d[P]/dt) = -(1/q)*(d[Q]/dt), holds true universally for all reactions, including zero-order, first-order, and second-order reactions. It is clarified that the rate law can differ for reactants A and B in complex reactions, where the stoichiometric coefficients relate to the reaction orders. The conversation concludes with a consensus on the validity of these principles in various reaction scenarios.

PREREQUISITES
  • Understanding of reaction kinetics and rate laws
  • Familiarity with stoichiometric coefficients in chemical reactions
  • Knowledge of zero-order, first-order, and second-order reactions
  • Basic grasp of differential calculus as it applies to reaction rates
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  • Study the derivation and application of the rate law in chemical kinetics
  • Explore the differences between elementary and complex reactions
  • Learn about the impact of limiting reactants on reaction rates
  • Investigate the role of stoichiometric coefficients in determining reaction order
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Chemistry students, researchers in chemical kinetics, and professionals involved in reaction mechanism studies will benefit from this discussion.

christian0710
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Hi I need some help understanding reaction kinetics, and I’m trying to get an overview, so I’d really appreciate some help. I have 3 individual/quite unrelated questions, if you have time to answer one that would be very much appreciated.

1. In what situations dos the Definition of the reaction rate for a general reaction Hold true?

aA + Bb --> pP+qQ

-(1/a)*(d[A]/dt)= -(1/b)*(d/dt) = -(1/p)*(d[P]/dt) = -(1/q)*(d[Q]/dt)

I would assume this definition only holds true when all the rates are equal, so this does not apply for reactions where the rate of A is different from the rate of B (if this is possible)

2. If the rate of A is slower than the Rate of B, would they then not be comsumed at the same RATE because A would be the limiting factor, the equation -(1/a)*(d[A]/dt)= -(1/b)*(d/dt) holds true for all reactions?

3. Is it true that if the rate law for A + B --> C +D is givn by -d[A]/dt = k[A]^n^m with respect to A, then it might be different with repsect to B? So -d/dt might be different (slower or faster) than -d[A]/dt, so the -d[A]/dt=-d/dt = k[A]^n*^m only holds true for elementary reactions, while for complex reactions the rate law for -d[A]/dt could be equal to k[A] raised to a first order while -d/dt could be equalt to k[A]^2^1 (something different?)
 
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christian0710 said:
I would assume this definition only holds true when all the rates are equal, so this does not apply for reactions where the rate of A is different from the rate of B (if this is possible)

It is not possible. I already told you somewhere else that we use stoichiometric coefficients to make sure rates of the reaction for all substances involved are identical.
 
Hi borek, yes i was a bit confused on what question you were answering but now it seems more clear to me: What you are saying is that No matte what reaction we have (Zero order, first order, second order, complex) the equation -(1/a)*(d[A]/dt)= -(1/b)*(d/dt) = -(1/p)*(d[P]/dt) = -(1/q)*(d[Q]/dt) is true? and in some cases the rate of any of the reactants might display the following relationship = k[A]^m^n (for complex reactions) and in elementary reactions the orders of the reaction equals the koefficients of the reactants?

If this is a correct understanding, I'm really happy :)
 
Ohh yes an just to make sure it's 100% clear for me:

If -(1/a)*d[A]/dt)=k[A]^m^n

Then This must also be true

-(1/b)*(d/dt)=k[A]^m^n

:)
 
christian0710 said:
No matte what reaction we have (Zero order, first order, second order, complex) the equation -(1/a)*(d[A]/dt)= -(1/b)*(d/dt) = -(1/p)*(d[P]/dt) = -(1/q)*(d[Q]/dt) is true?


and in some cases the rate of any of the reactants might display the following relationship = k[A]^m^n (for complex reactions) and in elementary reactions the orders of the reaction equals the koefficients of the reactants?


christian0710 said:
If -(1/a)*d[A]/dt)=k[A]^m^n

Then This must also be true

-(1/b)*(d/dt)=k[A]^m^n


Yes, yes, yes & yes.
 
Thank you very much Borek - Now I'm really happy :D
 

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