Integrated Rate Law for 2nd Order Reactions

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samy4408
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hello i have a question about kinetics : to have the integrated rate law for second order reaction the professor write the following
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why we don't write the rate like this : rate = -1/2(d[1]/dt) ?
why we ignore the stoichiometric coefficient ?
 
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"Rate of reaction" is often defined as (1/a)*d[A]/dt, where a is the stoichiometric coefficient of A (negative for reactants, positive for products). Then it's the same whichever reagent you look at, but it depends how you write the equation, e.g. it would be different for A → ½B or 4A → 2B. My preference is always to talk in terms of the rate of change of concentration of a specified reagent.