-307.28.1 Find the general solution to the system of DE

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SUMMARY

The discussion focuses on finding the general solution to the system of differential equations represented by the equations \(y'_1 = y_1 + 5y_2\) and \(y'_2 = -2y_1 - y_2\). The characteristic matrix \(A\) is defined as \(\begin{bmatrix} 1 & 5 \\ -2 & -1 \end{bmatrix}\), leading to the characteristic polynomial \(\lambda^2 + 9 = 0\). The roots of this polynomial, which are essential for determining the general solution, are complex and can be calculated as \(\lambda = \pm 3i\).

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Find the general solution to the system of differential equations
\begin{align*}\displaystyle
y'_1&=y_1+5y_2\\
y'_2&=-2y_1+-y_2
\end{align*}
why is there a $+-y_2$ in the given
ok going to take this a step at a time... so..$A=\left[\begin{array}{c}1 & 5 \\ -2 & -1 \end{array}\right]$
then
$\left[\begin{array}{c}1-\lambda & 5 \\ -2 & -1-\lambda \end{array}\right]
=\lambda^2+9$ ?
 
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yes, [math]\left|\begin{array}{cc}1- \lambda & 5 \\ -2 & -1- \lambda\end{array}\right|= (1- \lambda)(-1- \lambda)+ 10= -1- \lambda+ \lambda+ \lambda^2+ 10= \lambda^2+ 9= 0[/math].

Now, what are the values of [math]\lambda[/math]?
 
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