3rd order derivatives in the lagrangian

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SUMMARY

In classical field theory, terms in the Lagrangian cannot have more than two derivatives due to the violation of Poincaré invariance in quantum field theory. Specifically, if the canonical momentum \(\Pi(x,t)\) does not equal \(\dot{\phi}(x,t)\), the canonical commutation relations for Fourier components of the scalar field \(\phi(x,t)\) break down. This limitation is highlighted in Pierre Ramond's "Field Theory a Modern Primer" and is further illustrated by the Lorentz-Dirac equation, which, despite being Lorentz-invariant, exhibits non-causal behavior due to its third-order nature. Higher derivative theories necessitate exceptional fine-tuning to maintain consistency.

PREREQUISITES
  • Understanding of classical field theory concepts
  • Familiarity with quantum field theory and Poincaré invariance
  • Knowledge of canonical commutation relations
  • Basic grasp of Lagrangian mechanics and differential equations
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  • Study the implications of higher-order derivatives in classical mechanics
  • Explore the canonical quantization of scalar fields in quantum field theory
  • Investigate the Lorentz-Dirac equation and its non-causal effects
  • Read "Field Theory a Modern Primer" by Pierre Ramond for deeper insights
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I heard that in classical field theory, terms in the Lagrangian cannot have more than two derivatives acting on them. Why is this?

In quantum field theory, I read somewhere that having more than two derivatives on a term in the Lagrangian leads to a violation of Poincare invariance. Is this true?

One thing I derived is that, for a scalar field, if you accept the canonical commutation relations as true:

<br /> [\phi(x,t),\Pi(y,t)]=i\delta^3(x-y)<br />

then unless your canonical momentum \Pi(x,t) is equal to \dot{\phi}(x,t), then the commutation relations of the Fourier components of \phi(x,t) no longer obey equations like:

<br /> [a(k,t),a^\dagger(q,t)]=\delta^3(k-q)<br />

or using a different normalization scheme:

<br /> [a(k,t),a^\dagger(q,t)]=\delta^3(k-q)(2\pi)^32E_k<br />
 
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P.17 of Zee states this is because 'we don't know how to quantize actions with more than two time derivatives'. Why this is mathematically I do not know though (and was wondering the same thing myself...).
 
I found this in a book by some guy named Pierre Ramond, "Field Theory a Modern Primer".

"Third we demand that S [the action] leads to classical equations of motions that involve no higher than 2nd-order derivatives. Classical systems described by higher order differential equations will typically develop non-casual solutions. A well-known example is the Lorentz-Dirac equation of electrodynamics. It is a 3rd-order differential equation that incorporates the effects of radiation reaction and shows non-casual effects such as preacceleration of particles yet to be hit by radiation."

But this bugs me. I thought as long as your Lagrangian density is Lorentz-invariant, then the equations of motion will be Lorentz-invariant. So how can an equation that is Lorentz-invariant be non-causal?
 
The 2nd derivatives are actually first derivatives --- just integrated by parts. It is easier to consider non-field theory, but just a single particle. The Lagrangian is a function of position and velocity, and a "third derivative" would actually be a dependence on the 2nd derivative. Then see: http://www.tcm.phy.cam.ac.uk/~gz218/2010/01/higher-derivative-theories.html

In general, higher derivative theories require some exceptional fine-tuning to make sense.
 

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