- #1

karush

Gold Member

MHB

- 3,269

- 5

If $\displaystyle f(x)=\int_1^{x^3}\dfrac{1}{1+\ln t}\, dt$ for $x\ge 1$ then $f'(2)=$

(A) $\dfrac{1}{1+\ln 2}$

(B) $\dfrac{12}{1+\ln 2}$

(C) $\dfrac{1}{1+\ln 8}$

(D) $\dfrac{12}{1+\ln 8}$

ok I am little be baffled by this one due the $x^3$ in the limits

since from homework you just take integral and then plug in f'(x)

AP Calculus Exam PDF {WIP}

https://drive.google.com/file/d/131RCqemH8cHPh5FIW9VtqLPO4Kni0Bqo/view?usp=sharing

(A) $\dfrac{1}{1+\ln 2}$

(B) $\dfrac{12}{1+\ln 2}$

(C) $\dfrac{1}{1+\ln 8}$

(D) $\dfrac{12}{1+\ln 8}$

ok I am little be baffled by this one due the $x^3$ in the limits

since from homework you just take integral and then plug in f'(x)

AP Calculus Exam PDF {WIP}

https://drive.google.com/file/d/131RCqemH8cHPh5FIW9VtqLPO4Kni0Bqo/view?usp=sharing

Last edited: