4 Charges at the corners of a square

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Homework Help Overview

The problem involves calculating the electric field at the center of a square with charges placed at its corners. The square has a side length of 1 meter, and the charges include two positive charges of +4 µC, one positive charge of +3 µC, and one negative charge of -3 µC.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the electric field by plugging in values for charge and distance, but questions arise regarding the correctness of their approach and the final result. Participants discuss the direction of individual field vectors and the resultant field from the charges.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the cancellation of fields and the method of summing magnitudes. Some guidance has been offered regarding the addition of fields and the interpretation of results, but there is no explicit consensus on the final answer.

Contextual Notes

The discussion includes references to the original poster's confusion about the calculations and the need to clarify the method of summing electric fields from multiple charges. There is also mention of a textbook reference that influences the original poster's approach.

Ortix
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Homework Statement



Consider a square which is 1m on a side. Charges are placed at the corners of the square as follows:

+4 uC at (0,0)
+4 uC at (1,1)
+3 uC at (1,0)
-3 uC at (0,1)

What is the magnitude of the electric field at the square's center?

Homework Equations



E= k(Q/r^2)

(sorry i suck at latex, don't know how to use it)

The Attempt at a Solution



Well I thought this was fairly simple. I just plugged in Q and for r^2 i used cos(45)^2 since the the distance to the center is 1cos(45) = sqrt(2)/2

This gave me 3 different values. for the 4 uC's i got 71934.4 N/C, for the +3 i got 53950.8 and for the -3 i got -53950.8.

So these are the fields in their respective direction. To calculate the magnitude I sum them all, square them and then take the square root. That gives me 143868. However this is not one of the answers:

1.1E5
1.3E5
1.5E5
1.7E5

Anyone have any idea if i did something wrong?
 
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Could you show please the direction of the individual field vectors?

ehild
 
[PLAIN]http://img831.imageshack.us/img831/1600/unledss.jpg

I hope this is right

1 2 and 4 are positive whereas 3 is negative
 
Last edited by a moderator:
It is right. What can you say about the field of the two 4μC charges? What is the direction of the resultant?

ehild
 
Well it should cancel right? Since they are the same magnitude and opposite direction. So would i just sum field's 3 and 2, square them and then take the square root?
 
Well, you add only those two fields. You know their magnitudes, don't you? and they point in the same direction, so what is the magnitude of their sum? Why do you square and take the square root?

ehild
 
The reason why i square and take the square root is because my book says so :P But i realized that I already know the magnitude and direction (in the book it was calculated separately) so I just need to add them which gives me 107900. Is that correct? Would the answer be 1.1E5?
 
Ortix said:
The reason why i square and take the square root is because my book says so :P But i realized that I already know the magnitude and direction (in the book it was calculated separately) so I just need to add them which gives me 107900. Is that correct? Would the answer be 1.1E5?


Yes. :smile:

ehild
 
sweet! Thanks man :)
 

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