4 dimensional curl as antisymmetric matrix

  • Context: Graduate 
  • Thread starter Thread starter purplegreen
  • Start date Start date
  • Tags Tags
    Curl Matrix
Click For Summary
SUMMARY

The discussion centers on calculating the curl of a 4-dimensional matrix using Stokes' theorem. The curl is represented as an antisymmetric matrix with entries defined by the formula Mi,j = d Ai/d j - dAj/di. The confusion arises regarding the integral calculation in the x-y plane, specifically whether the result should be M1,2 ΔxΔy or -M12. The correct interpretation of the curl in 4 dimensions involves elements of the 6-dimensional Lie algebra so(4), represented by skew-symmetric real matrices.

PREREQUISITES
  • Understanding of Stokes' theorem in higher dimensions
  • Familiarity with antisymmetric matrices and their properties
  • Knowledge of Lie algebras and Lie groups, specifically so(4)
  • Basic concepts of vector calculus in multiple dimensions
NEXT STEPS
  • Research the properties of the 6-dimensional Lie algebra so(4)
  • Study the application of Stokes' theorem in 4-dimensional spaces
  • Learn about skew-symmetric matrices and their role in physics
  • Explore advanced vector calculus techniques in higher dimensions
USEFUL FOR

This discussion is beneficial for mathematicians, physicists, and researchers working with higher-dimensional calculus, particularly those interested in the applications of Lie algebras and antisymmetric matrices in theoretical frameworks.

purplegreen
Messages
4
Reaction score
0
I'm a bit confused. I'm trying to calculate the curl of a 4 dimensional matrix. It's an attempt to use stokes theorem for 4 dimensions.

The curl can be written as a antisymmetric matrix from what I understand with entries,

Mi,j = d Ai/d j - dAj/di

where i and j would be the different coordinates like x, y, z etc... However, from what I understood if you looked the integral about an infinitesimal square in the x-y plane you could work out the integral as:
(dAy/d x - dAx/dy)ΔxΔy

I was informed that this would gives M1,2 ΔxΔy
which would be wrong, you would get -M12 surely?

So how does the curl look in matrix/ tensor form for 4 dimensions?
Hopefully this makes some sense, sorry if it's a slightly confused question.
 
Physics news on Phys.org
In 4 dimensions the curl of a vector field is, geometrically, at each point an element of the ##6-##dimensional Lie algebra ##\mathfrak{so}(4)##, all skew-symmetric real matrices: ##v^*\otimes w - w^*\otimes v##.

You can search for this Lie algebra or Lie group for further information.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 6 ·
Replies
6
Views
13K
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K