4 questions regarding electric field

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Homework Help Overview

The discussion revolves around several questions related to electric fields, specifically focusing on calculations involving electric forces and fields generated by charges in various configurations. The subject area includes concepts from electrostatics and field theory.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss various approaches to solving specific questions, including the use of formulas for electric fields at the center of a circular arc. Some express uncertainty about their calculations, while others attempt to clarify concepts related to the integration of electric field components.

Discussion Status

The discussion is ongoing, with participants sharing different interpretations and approaches to the problems. Some guidance has been offered regarding the use of calculus to derive electric fields, and there is acknowledgment of the rules regarding providing complete solutions. Participants are actively seeking clarification on specific questions and concepts.

Contextual Notes

There are constraints regarding the sharing of complete solutions, as participants are reminded of the forum's rules. Some participants express confusion over specific calculations and the setup of problems involving multiple charges.

realz
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Homework Statement



Questions attached

Homework Equations



K=9X10*9
E=KQ/R*2
vf=vi+at

The Attempt at a Solution



I only have idea on question 14 but it's wrong. For others I don't , I can only do simple one like if all the charge in x axis

Question 14:
qE=ma
qE/m=a = 20
vf=vi+at
=50+20(2)
=90

*I've been told that all of the answers for the questions is A
 

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for Q9 we can use formulae for Electric Field at centre of a circular arc

E = (kq/r) * r*(sin(alpha))/alpha

where alpha is half the angle of arc. In this case alpha= 45
 
and Q10 is same as Q9
 
answer of Q12 :A
 
darkxponent said:
for Q9 we can use formulae for Electric Field at centre of a circular arc

E = (kq/r) * r*(sin(alpha))/alpha

where alpha is half the angle of arc. In this case alpha= 45
I don't get it. tried but it gave 3.53
darkxponent said:
and Q10 is same as Q9
can you upload worksheet
darkxponent said:
answer of Q12 :A
I can do if the point of charge is in y but now if it's in 2 side x and y, can you show me the way?

what about question 14?
 
Dont just mug up the formula. its easier to find it by simple calculus

attachment.php?attachmentid=37243&stc=1&d=1310885847.png


consider two element dx at angle θ from central element.
their field's sin components will cancell out and thus only cos will remain.
now just integrate.
 

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realz said:
I don't get it. tried but it gave 3.53

can you upload worksheet
i just uploaded it but they removed it because i solved the whole question. We can't provide whole solution as per rules of PF. I just read all the rules. And i am not going to break more rules because i already have received a warning. We can only help you solve it.

You should also read the rules https://www.physicsforums.com/showthread.php?t=414380 as you also new to this website.
 

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