Line Integral Question (Vertical line issues)

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SUMMARY

The discussion focuses on calculating the mass of a wire using line integrals along a piecewise linear curve from (2,2) to (12,4) and then to (12,9). The density function is defined as (xy) = 2xy + 6x. The first integral from (2,2) to (12,4) was computed to be approximately 890.629. The challenge arises in parametrizing the second segment from (12,4) to (12,9), where the correct parametric equation is established as r(t) = (12, 4 + 5t) for 0 ≤ t ≤ 1, with x(t) = 12 and y(t) = 4 + 5t.

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Homework Statement


A wire lies along the piecewise linear curve extending from the point (2,2) to the point (12,4) to the point (12,9). If the density of the wire is given by (xy)=2xy+6x, use a line integral to find the mass of the wire.


Homework Equations





The Attempt at a Solution


I know I need to do two separate line integrals and add them.

For the first half (2,2 to 12,4) I got
integral from 2 to 12 of [(2(t)((1/5)t+(8/5))+6t] sqrt(1+(1/5)^2) which comes out to be 890.629

For the second part, I know it should be integral from 4 to 9, but I'm having issues finding the correct equation for the line from (12,4) to (12,9).

I've tried just using the y parametrization of p(x,y) which is <t,(1/5)t+8/5>, but I'm not getting the right answers.

Can anyone help me out with this? I have an exam during the next week.

Thank you.
 
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A parametric equation of the line segment with the starting point (12,4) and end point (12, 9) is: r(t)=(1-t)(12,4)+t(12,9)=(12, 4+5t), where 0=<t=<1.

That is x(t)=12, and y(t)=4+5t. Now just parametrize the linear density, and integrate. Don't forget the ds term though.
 

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