- #1
cowgiljl
- 63
- 1
It has been at least 5 years since my last math class and I am kinda struggling.
The question is:
Use the intermediate value theorem to show that there is a root of ln x = e^-x on the interval (1,2). Find the correct root to 3 decimal values
What i have so far
f(1) = ln 1 - e^-1 = 0 which -.368< 0
f(2) = ln 2 - e^-2 = 0 which .558 > 0
am I doing this correct or am I really off base ?
thanks joe
The question is:
Use the intermediate value theorem to show that there is a root of ln x = e^-x on the interval (1,2). Find the correct root to 3 decimal values
What i have so far
f(1) = ln 1 - e^-1 = 0 which -.368< 0
f(2) = ln 2 - e^-2 = 0 which .558 > 0
am I doing this correct or am I really off base ?
thanks joe