5th order DE with g(x)=32exp^(2x)

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Homework Help Overview

The discussion revolves around solving a fifth-order differential equation using the method of variations of parameters. The specific equation is y''''' - 4y''' = 32exp^(2x), and participants are exploring the general solutions and the steps involved in the process.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the homogeneous solution and the use of the Wronskian determinant. There are questions about the correctness of their approaches and whether the dimensions of the matrix used in variations of parameters are appropriate. Some participants express uncertainty about the next steps in converting their results back to the original variable y.

Discussion Status

There is ongoing exploration of the problem, with participants attempting different approaches and sharing their findings. Some guidance has been offered regarding simplifying the differential equation and using substitutions. Participants are actively seeking clarification on their methods and results.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is an emphasis on understanding the steps rather than providing complete solutions.

leyyee
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Homework Statement



Use variations of parameters to find the general solutions of the following differential equations.

y'''''-4y'''=32exp^(2x)

Homework Equations



no relevant equations.

The Attempt at a Solution



hey there, I tried solving this question. I got the homogeneous equation.

yh(x)=C1+C2x+C3X2+C4exp^(2x)+C5exp^(-2x)

but after this step.. I am stuck..

Because I am not quite sure whether I am in the correct path to look for the general solutions. After I have this equation, I did the wronskian matrix, I found the determinant of the 5X5 matrix is 512. Am I correct? Please correct me if I am not in the journey to my answer.

Besides that , If I were to use the variations of parameters. The matrix would be 5X5 dimensions. Is it correct?

Thanksedited due to duplication on the template question.. sorry..
 
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You should get into the habit of reducing such a DE into something more familar. Let [tex]u=y^{(3)}[/tex], so the DE becomes [tex]u'' - 4u = 32e^{2x}[/tex].

Proceed as usual (involves a 2x2 matrix) to solve for u(x). Then you can obtain y(x).
 
hey there.
thanks a lot for the reply..

i will try out your attempt.. then i will post if i need anymore help..
thanks
 
hey there, i have tried out your attempt.. but I only can find the general solutions

the wronskians i found was -4, am I in the right path ?

u(x) = uh(x) + up(x) = C1e2x+C2e-2x+8xe2x-2e2x

how should I convert it to y(x) = yh(x) + yp(x)

If i use the equation u gave me u = y(3). Am I suppose to integrate u(x) by 3 times?any clue for me?

thanks
 
Last edited:
leyyee said:
hey there, i have tried out your attempt.. but I only can find the general solutions

the wronskians i found was -4, am I in the right path ?

u(x) = uh(x) + up(x) = C1e2x+C2e-2x+8xe2x-2e2x
Well done!

leyyee said:
how should I convert it to y(x) = yh(x) + yp(x)
No need; you've done the variation of parameters work for u.

leyyee said:
If i use the equation u gave me u = y(3). Am I suppose to integrate u(x) by 3 times?
Exactly!
 
Wow.. thanks a lot.. I think I will post the proper solutions after I finished the steps ok ?

and I will let you go through my answer to see whether I did any mistakes.. Thanks
 

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