64 events occurring in the flipping of a die

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Discussion Overview

The discussion revolves around the concept of determining 64 events related to the flipping of a die, specifically focusing on the outcomes of rolling a six-sided die. Participants explore the mathematical implications and combinatorial aspects of die rolls.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant, kautilya, seeks clarification on the 64 events, initially suggesting they refer to outcomes from rolling a six-sided die.
  • Another participant questions whether the reference is to outcomes or to muscle movements involved in rolling the die.
  • Some participants clarify that a single roll of a six-sided die results in only six outcomes, while rolling two six-sided dice yields 36 outcomes, and three yields 216.
  • There is a suggestion that rolling two eight-sided dice or three four-sided dice could yield 64 outcomes, indicating a need for clarification on the type of die being discussed.
  • One participant emphasizes that the discussion is more about combinatorics rather than probability, noting that probability becomes relevant when considering the likelihood of specific outcomes.
  • A later reply proposes a method to generate 64 equiprobable outcomes through a specific average number of rolls, though it is noted that achieving exactly 64 outcomes with standard six-sided dice is not straightforward.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to achieve 64 outcomes with a six-sided die, and multiple competing views regarding the interpretation of the question and the methods to obtain the desired outcomes remain evident.

Contextual Notes

There are unresolved assumptions regarding the type of die being referenced and the specific nature of the 64 events. The discussion also highlights the distinction between combinatorial counting and probability calculations without resolving the mathematical steps involved.

kautilya
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Hi there,

I am trying to figure out the 64 events occurring in the flipping of a die. Can someone help me with this?

regards
kautilya
 
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Can you elaborate? Do you mean 64 outcomes of the die roll, or do you mean 64 muscle movements that go into throwing the die?
 
Is this an ordinary six-sided die? An eight-sided die (e.g. shaped like an octahedron) could lead to 64 possible outcomes if you rolled it twice.
 
Thanks a lot Dave and belliott.

Yes, i meant the 64 outcomes of the die roll of a six-sided die. Can you help me obtain this using the laws of probability?

regards
kautilya
 
We don't know what you mean. You'll have to tell us more if you want a sensible answer. To me, a die roll is an abstract event with exactly six equiprobable outcomes.
 
kautilya said:
Thanks a lot Dave and belliott.

Yes, i meant the 64 outcomes of the die roll of a six-sided die. Can you help me obtain this using the laws of probability?

regards
kautilya

Yes, as CRG points out, a single roll of a 6-sided die results in one of only six outcomes, all of which are equally probable.

If you roll two D6, then the number of possible outcomes rises to 36.
3 dice gets you 216.

I don't know any way of getting 64.

Sure it was 6-siders?
Rolling 2 8-siders would get you 64, as would rolling 3 4-siders...
 
Of course, none of this has to do with probability - it's just basic combinatorics, i.e. counting the number of possible outcomes. Probability enters only when you start to ask about the liklihood of a given outcome, that is, the fraction of all possible outcomes that will produce the given outcome, e.g. the number of ways to roll at least one "three" in four rolls of the die.
 
DaveC426913 said:
I don't know any way of getting 64.

Even/odd sequence after 6 rolls? :wink:

Edit: Turning that to a serious response, I can generate 64 equiprobable outcomes in 760/243 ≈ 3.13 fair die rolls on average. Is a better result possible? It can't be done with two rolls, since 6^2 = 36 < 64. It can't always be done in 3 rolls, since 6^3 = 216 is not divisible by 64 so some outcomes would be more likely than others.
 
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