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karush

Gold Member

MHB

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7.4.32 Evaluate the integral

$\displaystyle \int_0^1\dfrac{x}{x^2+4x+13}\, dx$

ok side work to complete the square

$x^2+4x=-13$

add 4 to both sides

$x^2+4x+4=-13+4$

simplify

$(x+2)^2+9=0$

ok now whatW|A returned ≈0.03111

$\displaystyle \int_0^1\dfrac{x}{x^2+4x+13}\, dx$

ok side work to complete the square

$x^2+4x=-13$

add 4 to both sides

$x^2+4x+4=-13+4$

simplify

$(x+2)^2+9=0$

ok now whatW|A returned ≈0.03111

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