8*pi in the Einstein field equations?

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The discussion centers on the Einstein field equations, specifically the term 8π in the equation R_{\mu\nu}-\frac{1}{2}Rg_{\mu\nu}+\Lambda g_{\mu\nu}=\frac{8\pi G}{c^4}T_{\mu\nu}. Participants question the necessity of the 8π factor, emphasizing that it ensures the equations align with Newtonian gravity in the appropriate limit. The inclusion of this term is crucial for maintaining consistency between general relativity and classical physics. The conversation highlights the importance of unit compatibility in the equations. Understanding the role of 8π is essential for grasping the relationship between gravity and spacetime in Einstein's theory.
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A typical formulation of the Einstein equations is

R_{\mu\nu}-\frac{1}{2}Rg_{\mu\nu}+\Lambda g_{\mu\nu}=\frac{8\pi G}{c^4}T_{\mu\nu}

The \frac{G}{c^4} make the units work out. What about the 8*pi? Why is this necessary?
 
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The field equations have to agree with Newtonian gravity in the Newtonian limit.
 
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In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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