9 pm, and still dont understand

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Homework Help Overview

The problem involves a rifle bullet fired at an angle of 30 degrees below the horizontal from a height of 80 meters with an initial velocity of 800 m/s. The objective is to determine how far from the base of the cliff the bullet strikes the ground below, considering gravitational acceleration of 9.8 m/s².

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use a formula involving the initial velocity and angle to calculate the range but expresses confusion over the resulting value. Some participants suggest resolving the initial velocity into its X and Y components using trigonometry and applying kinematic equations, while others note the need for understanding these equations.

Discussion Status

Participants are exploring different methods to approach the problem, with some offering guidance on resolving vectors and using kinematic equations. There is a recognition of the original poster's struggle with the concepts, and encouragement is provided to help them understand the necessary steps.

Contextual Notes

The original poster indicates a lack of familiarity with kinematic equations and expresses concern about their understanding of the material, which may impact their ability to solve the problem effectively.

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Homework Statement


A rifle bullet is fired at an angle of 30 degrees below the horizontal with an initial velocity of 800 m/s from the top of a cliff 80 m high. How far from the base of the cliff does it strike the level of ground below
g=9.8
initial velocity- 800 m/s
y=80 m


Homework Equations


People i ask say..
R=(initial velocity squared x sin(2 theta)
g




The Attempt at a Solution


i did
800^2 x sin2(30)
9.8

i get 56556.76106-which seems way to high
Then i did Soh Cah Toa
Sin=Opp/Adj
56556.76106/80
and got 706.9595133

I really just don't understand what i am doing, and need help. bad. this is due tomorrow.
 
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Hello welcome to Physicsforums! Hope you will learn here and also teach us what you know!

For the problem:
(1)You must resolve the initial velocity into their X and Y coordinates using trigonometry.
(2)Then use kinematic equations to solve the problem.
 
I don't even know any of that.
We never learned Kinematic equations.
Im very slow at this, and am now regretting taking this class.
 
Hey don't despair! I can teach you what I know. I am learning this myself.

Kinematic Equations:
S=volt+0.5at^2
S=Vft-0.5at^2
S=((Vo+Vf)/2)*t
Vf=Vo + at
Vf^2=Vo^2 + 2aS

S=Displacement in metres
Vo=Initial Velocity in metres/second
Vf=Final Velocity in metres/second
a=acceleration in metres/second squared
t=time in seconds

For all kinematic problems, write your 5 variables down and write the known values in.

Velocity is a vector quantity. It has magnitude and DIRECTION. direction is usually indicated by an angle as in your problem.

Velocity of the bullet is 800m/s angle 30degrees below the horizontal. Draw a picture and see if you can resolve the velocity into X and Y coordinates.

Have a look at this site:
http://www.glenbrook.k12.il.us/gbssci/phys/Class/vectors/u3l2c.html

Then we will see if we can solve the problem. Please come back.
 
Last edited by a moderator:
megg0230 said:
I don't even know any of that.
We never learned Kinematic equations.
Im very slow at this, and am now regretting taking this class.
http://www.mathlinks.ro/Forum/latexrender/pictures/b/0/2/b02ab4a44802a89197dc4fcc4947b1ec33ebdf9d.gif
 
Last edited by a moderator:
Here is a better site.

http://id.mind.net/~zona/mstm/physics/mechanics/curvedMotion/projectileMotion/generalSolution/generalSolution.html
 
Last edited by a moderator:
use the 2nd equation to find time

keep in mind the bullet is being fired DOWN, so your y value must be negative

when you find time, disregard the negative value

then use the 1st equation to find x
 

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