A 15 LB weight is dropped vertically 1 ft

  • Thread starter Thread starter Nornh
  • Start date Start date
  • Tags Tags
    Weight
Click For Summary
SUMMARY

A 15 LB weight dropped vertically from a height of 1 ft experiences a change in momentum upon impact. The final velocity can be calculated using the equation v² = v₀² + 2gh, resulting in a speed of 8 ft/sec just before impact. However, if the weight is stopped instantaneously, the force exerted at impact becomes theoretically infinite due to the lack of time for deceleration, as per Newton's law F = ma. This discussion highlights the distinction between inertia and mass, clarifying that the perceived increase in impact force is not due to increased weight but rather the required force to stop the object.

PREREQUISITES
  • Understanding of Newtonian mechanics
  • Familiarity with concepts of momentum and kinetic energy
  • Knowledge of gravitational acceleration (g = 32 ft/s²)
  • Ability to apply basic physics equations, such as v² = v₀² + 2gh
NEXT STEPS
  • Study the principles of momentum and impulse in physics
  • Learn about the implications of instantaneous force and its theoretical aspects
  • Explore the relationship between potential energy and kinetic energy in falling objects
  • Investigate real-world applications of Newton's laws in impact scenarios
USEFUL FOR

Physics students, engineers, and anyone interested in understanding the dynamics of falling objects and the forces involved in impact scenarios.

Nornh
A 15 LB weight is dropped vertically 1 ft. and is stopped instantaneously. What is the weight at impact due to inertia?

That wasn't quite the answer I needed.


Question:

From "0" velocity the 15lb object is released vertically at a 1 ft drop and then it is instantaneously stopped. What is the force in lbs of the object at that point?
 
Last edited by a moderator:
Physics news on Phys.org
A 15 LB weight is dropped vertically 1 ft. and is stopped instantaneously. What is the weight at impact due to inertia?

hey,
so far i understand , you need to find the change in momentum per unit time that will give you the force i mean the weight at impact.

the initial momentum is 0 becasue initially the weight was at rest.

for the final momentum P=mv you need v to calculate.

so use the equation v^2= v0^2 + 2gh
v0= the initial velocity =0, g acceleration due to gravity and h the distance it travelled.
i hope this will help you.

bye
SKT
 
Another way to find the speed after the weight has fallen 1 foot is to use kinetic energy. When the weight is first released, it has 0 kinetic energy and potential energy 15 pounds*1 foot= 15 foot-pounds.

After it has fallen the 1 foot, it's potential energy is 0 and it's kinetic energy is (1/2)mv2= 15. The mass of a 15 pound weight is 15/32 poundas so (15/64)v2= 15. v2= 64 and v= 8 ft/sec.

In stopping, it changes speed by -8 ft/sec (from 8 to 0).

HOWEVER! You have a serious problem- Force is "change in speed over change in time" and there is NO "change in time". You have specified that the weight is stopped "instantaneously". That can be done only by an infinite force!
 
hi HallsofIvy


thanks, so what do you suggest then,

what should be the weight at the time of imapct? is it infinite ?
SKT
 
I feel there is some pre-scientific thinking going on here. Children observe that a rock makes a bigger crater in the sand if it is dropped from a greater height. So they believe that a moving body is heavier than a resting body. I think this was a widely accepted concept in ancient times, too.
Newtonian mechanics claim that the larger crater is due to the larger inertial force required to stop the rock, and not due to an increased mass of the rock.
You could ask, what is the force exerted by the falling body onto the ground. But if the stopping is 'instantaneous', the answer would be an 'infinite' force via Newton's law F = ma.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
5K