A 2.8-kg block slides over the smooth icy hill -- Find the minimum speed to clear the pit

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SUMMARY

The discussion centers on calculating the minimum speed required for a 2.8-kg block to clear a pit after sliding over a smooth icy hill. The participants emphasize the importance of understanding the relationship between horizontal forces and work done, specifically referencing the equation W=Fd, where W represents work, F is the force, and d is the distance traveled. The need for clarity on the horizontal force acting on the block is highlighted as crucial for solving the problem.

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nouvelague
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Homework Statement
A 2.8-kg
block slides over the smooth, icy hill shown in the figure (Figure 1). The top of the hill is horizontal and 70 m
higher than its base.
Figure1 of 1

Part A
What minimum speed must the block have at the base of the hill so that it will not fall into the pit on the far side of the hill?
Express your answer using two significant figures.

I'm assuming that since this has to go over the pit, it would have to then travel 160m and since it is horizontal distance it would have something to do with Fx, and therefore W=Fd? But also, there is going to be a vertical component, in that case mgh as well, and I have to solve for speed, so I need kinetic energy as well. But am I am not sure how to approach these problems or arranging the equations.
Relevant Equations
W=Fd
KE = 1/2 mv^2
PE = mgh
Screenshot 2024-10-19 211539.png
 
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nouvelague said:
it would have to then travel 160m and since it is horizontal distance it would have something to do with Fx, and therefore W=Fd?
What would F be here? If you are going to multiply it by a horizontal distance then it must be a horizontal force. What horizontal force?
 
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