A+2b=2a+b=>1=2. please tell me what is the problem

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The discussion centers on the algebraic manipulation of the equation a + 2b = 2a + b, leading to the erroneous conclusion that 1 = 2. The critical error arises from dividing by zero when simplifying a - b = 2(a - b) under the assumption that a = b. The correct interpretation emphasizes that the equality ax = bx only holds when x is nonzero, highlighting the necessity of avoiding division by zero in algebraic proofs.

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if we get:

a+2b=2a+b
=>a-b=2a-2b
=>a-b=2(a-b)
=>1=2

I can't figure out the problem in it..please tell me
 
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Does 2*0=3*0 also imply 2=3??
 
waqarrashid33 said:
if we get:

a+2b=2a+b
So 2b- b= 2a- a which gives a= b.

=>a-b=2a-2b
=>a-b=2(a-b)
=>1=2
Since a= b, a- b= 0 and you cannot divide by 0.0

I can't figure out the problem in it..please tell me
 
Note that the law

ax=bx~\Rightarrow~a=b

Only holds if x is nonzero!

The correct way in solving this is

ax=bx~\Rightarrow~ ax-bx=0~\Rightarrow~(a-b)x=0~\Rightarrow ~a-b=0~\text{or}~x=0
 

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