A 9.0 killogram mass and a 3.0 kg mass are at rest on a frictionless

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Homework Help Overview

The problem involves two masses on a frictionless table, one weighing 9.0 kg and the other 3.0 kg, with a compressed spring between them. After the thread holding them together breaks, the 9.0 kg mass moves with a velocity of 2.0 m/s, and the task is to determine the velocity of the 3.0 kg mass.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of momentum conservation and question the interpretation of the final velocities. There is a focus on understanding the initial conditions and the implications of the spring's force on the two masses.

Discussion Status

Some participants have offered insights into the relationship between the masses' accelerations and velocities, while others are exploring the implications of the system's momentum. There is an ongoing examination of the assumptions regarding the motion of the masses after the thread breaks.

Contextual Notes

Participants note that the masses start from rest and move in opposite directions after the thread breaks, which is a key aspect of the problem's setup.

scbeturner
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1. a 9.0 killogram mass and a 3.0 kg mass are at rest on a frictionless table. A massless spring is compressed between the masses, which are held together by a thread. The thread breaks and the 9.0 kg mass moves to the left with a velocity of 2.0 m/s. Find the velocity of the 3.0 kg mass.



2, m1v1+m2v2=(m1+m2)v3



3. 9(2)+3
18+0=12v3
v3=1.5m/s
this was my original attempt, but i realize it is not solving for the velocity of the 3.0kg mass but i don't know what else to do
 
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What does v3 mean? ehild
 


It stands for the final combined velocity but i am not sure if this equation is right for this problem.
 


No, it is not the final combined velocity. Read the problem: the final velocity of one mass is 2 m/s and you need to find the velocity of the other mass. So there is no combined final velocity. But what do you know about of the initial velocities? Do the masses move?

ehild
 


The masses are initially at rest and then they move in opposite directions
 


scbeturner said:
The masses are initially at rest and then they move in opposite directions

What is the momentum of the system then?

ehild
 


The force that moves the blocks after the thread breaks?
 


scbeturner said:
1. a 9.0 killogram mass and a 3.0 kg mass are at rest on a frictionless table. A massless spring is compressed between the masses, which are held together by a thread. The thread breaks and the 9.0 kg mass moves to the left with a velocity of 2.0 m/s. Find the velocity of the 3.0 kg mass.



2, m1v1+m2v2=(m1+m2)v3



3. 9(2)+3
18+0=12v3
v3=1.5m/s
this was my original attempt, but i realize it is not solving for the velocity of the 3.0kg mass but i don't know what else to do


The spring will apply the same sized force on each mass - but opposite in direction.

because the masses are 9kg and 3 kg, the effect of the force on the 3 kg mass will give 3 times the acceleration it causes to the 9kg mass.

That means the 3kg mass will be traveling at 3 times the speed of the 9kg mass at all times.

It sounds like after a while the masses have moved away from the spring. By then the 9 kg mass has accelerated to 2.0 m/s

What do you think that means for the 3 kg mass?
 


That its speed is 6m/s?
 
  • #10


scbeturner said:
That its speed is 6m/s?

That sounds entirely reasonable!
 
  • #11


Thank you so much!:)
 

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