A Ball is rolling on a flat surface

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SUMMARY

The discussion centers on the dynamics of a ball rolling on a flat surface, specifically addressing the role of static friction and energy conservation. It is established that a ball will not accelerate indefinitely on a flat surface due to the absence of net forces acting on it, as static friction does not apply any net force or torque to a resting ball. The conversation clarifies that while rolling resistance and aerodynamic drag can cause deceleration, static friction facilitates rolling without energy loss, allowing the use of energy conservation principles in scenarios like rolling down an incline.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of static friction and rolling resistance
  • Knowledge of energy conservation principles in physics
  • Basic grasp of rotational dynamics, including moment of inertia
NEXT STEPS
  • Study the effects of rolling resistance on different surfaces
  • Explore the mathematical derivation of energy conservation in rolling motion
  • Investigate the role of static friction in various motion scenarios
  • Learn about the dynamics of objects on inclined planes and the forces involved
USEFUL FOR

Physics students, educators, and anyone interested in understanding the mechanics of rolling motion and energy conservation principles in classical mechanics.

atos
Let's say we have a rolling without slipping (e.g. mentioned ball) on flat surface.
Does it mean that the ball will accelerate to infinity ?
 
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atos said:
Let's say we have a rolling without slipping (e.g. mentioned ball) on flat surface.
Does it mean that the ball will accelerate to infinity ?
Why would it accelerate at all? Is it an incline?
 
No, it's a flat surface. But it seemed to me that since we have static friction, it means that the angular and linear acceleration is non-zero.
 
If it's friction it's decelerated (on the average) and thus coming to a halt. Roll a ball on a flat surface, and you can even observe this in Nature ;-).
 
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Ok, but I've heard that's because of rolling resistance (rolling friction) and not the static friction. I assume that we have situation without rolling resistance.
 
Any friction conteracts the motion and thus leads to deceleration. This must be so, because as a dissipative process friction leads to an energy loss of the moving object, heating up the environment.
 
Now I'm really confused. So why can we use the principle of conservation of energy, for example when the ball rolls down an incline :
mgh = \frac{mv^2}{2} + \frac{I\omega ^2}{2}
?
 
atos said:
Now I'm really confused. So why can we use the principle of conservation of energy, for example when the ball rolls down an incline :
mgh = \frac{mv^2}{2} + \frac{I\omega ^2}{2}
?
We can use the equation as an approximation.
There will be frictive losses which you could represent with an extra term on the right, but we don't know how big they will be and in most cases, friction is fairly negligible

As to your previous question, obviously the ball won't accelerate.
It would violate conservation of energy and momentum as well as intuition...
or have you ever seen a ball start to roll for no apparent reason?

Static friction does not apply any net force or torque to a resting ball.

Only a rolling ball will experience friction (in the direction opposite to its movement).
 
In the case of a ball rolling on a flat horizontal surface, and absent any forces such as rolling resistance or aerodynamic drag, then static friction is zero. The ball continues to roll at constant velocity.
 
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  • #10
atos said:
Now I'm really confused. So why can we use the principle of conservation of energy, for example when the ball rolls down an incline :
mgh = \frac{mv^2}{2} + \frac{I\omega ^2}{2}
?
Very simple: You neglect friction here. Since the constant force is obviously conservative then the energy-conservation law holds.
 
  • #11
atos said:
Now I'm really confused. So why can we use the principle of conservation of energy, for example when the ball rolls down an incline :
mgh = \frac{mv^2}{2} + \frac{I\omega ^2}{2}
?

vanhees71 said:
Very simple: You neglect friction here. Since the constant force is obviously conservative then the energy-conservation law holds.
Static friction is not ignored, as static friction is what causes the ball to roll instead of slide. Since the ball is not sliding, then there are no losses related to friction. The idealizations here are that there is no rolling resistance, and there is no aerodynamic drag. Static friction doesn't cause a loss of mechanical energy; it just converts some of the gravitational potential energy into angular kinetic energy as the ball rolls down the inclined plane.
 
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