1. The problem: In the capacitor circuit shown below C1 = 4␣F, C2 = 12␣F, C3 = 12␣F, and C4 = 3␣F. The switch (S) between A and B is closed and the energy stored in C3 is 1.35x10-3 J. If the switch is now opened calculate the change in the charge on C2. Assume the potential difference between C and D is constant. Here is the work that I have: (sorry the picture is too big to directly link) http://i.imgur.com/qnTvK.jpg The question asks what is the change in charge in C2 (the one on the lower left). The correct answer is -99uC but I can't even get my answer close.