A Block Sliding Down an Incline

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SUMMARY

The discussion focuses on calculating the work done by gravitational and normal forces on a 5 kg block sliding down a 30-degree incline with a coefficient of kinetic friction of 0.436. The work done by gravity is calculated as 61.25 J using the formula Wgravity = mgh, where h is the vertical height of the incline. The participant seeks clarification on the work done by the normal force, questioning whether it is equivalent to the work done by gravity, while also acknowledging the presence of friction as a complicating factor.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of work and energy
  • Knowledge of trigonometric functions related to right triangles
  • Basic principles of friction in physics
NEXT STEPS
  • Learn how to calculate work done by normal force in inclined planes
  • Study the effects of friction on work and energy in mechanical systems
  • Explore the relationship between gravitational potential energy and kinetic energy
  • Investigate the application of free body diagrams in solving incline problems
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to forces on inclined planes.

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Homework Statement



Starting from rest, a 5 kg block slides 2.5 m down a rough 30 degree incline. The coefficient of kinetic friction between the block and the incline is 0.436. The acceleration of gravity is 9.8 m/s2.

Find the work done by the force of gravity.

Find the work done by the normal force.

Homework Equations



Wgravity = mgh

The Attempt at a Solution



I figured out work done by force of gravity:

Wgravity = (5 kg)(9.8 m/s2)(2.5sin30) = 61.25 J

However, I don't know how to find the work done by the normal force. Is it the same as work done by gravity?
 
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There is another force involved - friction.
 

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