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A body moving with simple harmonic motion has an amplitude of 1

  1. Jun 3, 2012 #1
    A body moving with simple harmonic motion has an amplitude of 1 meter and the time for one complete oscillation is 2 seconds . Determine the velocity and acceleration of the body after 0.4 second from the mean position ?

    this is the answer :
    Vx = w root(r^2-x^2)
    ax=w^2.X

    w= 2Pi/t = 2Pi/2 = Pi rad/s
    x=rcosewt
    = 1 X cos Pi X 0.1 =
    cose18= 0.95

    Using
    Vx = w root(r^2-x^2)
    Vx = PI X root(1^2 - 0.95^2 )
    Vx = 0.98 m/s

    ax = W^2.X
    =Pi^2 0.95
    ax = +.37 m/s^2

    My questions now form where they got t = 0.1 and and how they find X = 0.95
    (the answer is not clear can please explain to me the answer )
     
  2. jcsd
  3. Jun 3, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
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    hi manal950! :smile:

    (try using the X2 button just above the Reply box :wink:)

    0.4 s is 0.4π radians, = 72°

    and the mean position is at 90°

    so 72° from the mean position is at 18° (and cos18° = 0.95) :wink:
     
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