MHB A bomb is dropped from an airplane

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Airplane Bomb
Click For Summary
When a bomb is dropped from a moving airplane, it retains the horizontal velocity of the plane, resulting in a parabolic trajectory relative to the ground. While it appears to fall straight down from the airplane's perspective, it actually travels forward as it descends. The problem illustrates concepts of differentiation and motion, emphasizing the difference in reference frames. This scenario is commonly used in physics to demonstrate the principles of projectile motion. Understanding these dynamics clarifies how the bomb's path relates to the airplane's movement.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
View attachment 1553

this looks like a very easy problem but I was ? about the bomb not dropping really in a vertical direction but implies that when it hits the ground it will right over the plane?
this was under exercises for differentiation but don't why it would be used for this
no ans in bk on this one..
 
Physics news on Phys.org
Re: a bomb is dropped from an airplane

karush said:
View attachment 1553

this looks like a very easy problem but I was ? about the bomb not dropping really in a vertical direction but implies that when it hits the ground it will right over the plane?
this was under exercises for differentiation but don't why it would be used for this
no ans in bk on this one..
Given that the airplane is moving at some rate, the bomb will be moving at the same rate in the horizontal (i.e. $x$) direction the instant it's released from the plane. From the reference frame of the ground, the bomb takes on a parabolic trajectory (where it's path is given by the equation $s(t)=-16t^2+s_0$). However, from the reference frame of the plane, it will appear as if the bomb is falling straight down.

Does this clarify things?
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
3
Views
6K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
6
Views
2K