A bomb is dropped from an airplane

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SUMMARY

The discussion centers on the physics of a bomb dropped from a moving airplane, specifically addressing the trajectory of the bomb. When released, the bomb retains the horizontal velocity of the airplane, resulting in a parabolic path as described by the equation \(s(t)=-16t^2+s_0\). This means that while the bomb appears to fall vertically from the airplane's perspective, it actually follows a curved trajectory relative to the ground. The problem is categorized under differentiation exercises, highlighting its application in physics and calculus.

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View attachment 1553

this looks like a very easy problem but I was ? about the bomb not dropping really in a vertical direction but implies that when it hits the ground it will right over the plane?
this was under exercises for differentiation but don't why it would be used for this
no ans in bk on this one..
 
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Re: a bomb is dropped from an airplane

karush said:
View attachment 1553

this looks like a very easy problem but I was ? about the bomb not dropping really in a vertical direction but implies that when it hits the ground it will right over the plane?
this was under exercises for differentiation but don't why it would be used for this
no ans in bk on this one..
Given that the airplane is moving at some rate, the bomb will be moving at the same rate in the horizontal (i.e. $x$) direction the instant it's released from the plane. From the reference frame of the ground, the bomb takes on a parabolic trajectory (where it's path is given by the equation $s(t)=-16t^2+s_0$). However, from the reference frame of the plane, it will appear as if the bomb is falling straight down.

Does this clarify things?
 

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