A box with the mass m = 25 kg is sliding up a hill

• Danielheidarr
In summary, the DJ Use tips from another thread to upload files to his Ipad and he has trouble understanding how to do it.f

Danielheidarr

Homework Statement
A box with the mass m = 25 kg is sliding with starting speed of V0=7m/s up a hill that has the angle Θ=12°. there is a steady wind blowing with a horizontal force of Fv = 50N. The coefficient of friction is µk = 0.18.
Relevant Equations
a) What is the force that works on the box from the hill?
b) What distance, L, does the box slide up the hill before it stops?
c) What does the coefficient of friction need to be at the lowest so the box doesn´t slide back down the hill*
What I have already attempted is on my Ipad and I don't know how to upload it on here.
With hope of help
DJ

topsquark and MatinSAR
there is a steady wind blowing with a horizontal force of Fv = 50N.
Which way?

MatinSAR
Which way?
Upp the hill (with the box)

Upp the hill (with the box)
You mean to say that there is an uphill component. The 50 N wind is horizontal.

If the wind is blowing down a slope, I guess it can't be horizontal.

Blowing horizontally into the slope is perhaps more precise than up the slope.

You mean to say that there is an uphill component. The 50 N wind is horizontal.
yeah that's what I meant sorry

You mean to say that there is an uphill component. The 50 N wind is horizontal.
sorry the uphill component is only for the box, the box is moving to the right towards the hill and the wind is moving horizontal in the same direction as the box.

If the wind is blowing down a slope, I guess it can't be horizontal.

Blowing horizontally into the slope is perhaps more precise than up the slope.
yeah what i meant to say is blowing horizontally into the slope.

This is what I did. What do you guys think?

Here is a pdf probably better to view that

Attachments

• Note 17 Nov 2022.pdf
694.1 KB · Views: 37
This is what I did. What do you guys think?
##6.5m## looks like the distance without the wind blowing.

ah that's right i forgot to add that in thank you so much :)

PeroK
Same for part c). ##\mu = \tan \theta ## is the calculation without the wind.

Danielheidarr
Same for part a.

Same for part a.
I'm not quite sure how to work the wind into the equation. Any hints for it?

I'm not quite sure how to work the wind into the equation. Any hints for it?
It's a force like any other.

I'm not quite sure how to work the wind into the equation. Any hints for it?
See post #5.

This is too hard to read. The subscripts are illegible and the thumbnail sketch FBD far too small. Draw decently sized diagrams and type equations.
Don't forget the wind force has a component normal to the slope.

This is too hard to read. The subscripts are illegible and the thumbnail sketch FBD far too small. Draw decently sized diagrams and type equations.
Don't forget the wind force has a component normal to the slope.
I also sent the pdf in post #12 better view there