A bullet of mass 7.00 g is fired horizontally into a wooden block of mass 1.29 kg resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.180. The bullet remains embedded in the block, which is observed to slide a distance 0.230 m along the surface before stopping.(adsbygoogle = window.adsbygoogle || []).push({});

What was the initial speed of the bullet?

Okay, first off, I know the block is sliding after the collision so that is internal energy.

[tex]\Delta[/tex]U_{internal}= Friction Force* Distance

=(12.7106N)(.180)(.230m) = 0.52621884J

From here, i do not know what to do.

Here was what I attempted:

KE=[tex]\Delta[/tex]U_{internal}

so

.5(1.297kg)v^2 = 0.52621884J

Velocity of the block was 0.9007m/s

Then I used Conservation of Momentum

Pi = Pf

.007kgV = (1.297kg)(.9007m/s)

V=166.9m/s

I don't know, seems slow for a bullet.

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# A bullet and a block (Momentum)

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