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Just to double check, Linear Momentum

  1. Oct 25, 2015 #1
    1. The problem statement, all variables and given/known data
    A bullet of mass 100 grams is fired horizontally into a 15 kilogram block of wood resting on a horizontal surface and embeds itself in the block. If the muzzle speed of the bullet is 250 meters per second, what is the velocity of the block containing the embedded bullet immediately after the impact?

    Given:
    Bullet with weight of 0.1kg (100g) fired horizontally with a velocity of 250 m/s
    Wooden block at rest weighing 15kg
    2. Relevant equations
    (1/2)(mass)(velocity^2) = KE

    3. The attempt at a solution
    (1/2)(0.1kg)(250m/s^2) = 3125 Joules <-- Kinetic energy of bullet
    Convservation of Energy
    (1/2)(15kg)(v^2) = 3125
    V^2 = 416.666...
    V = 20.412 m/s
     
  2. jcsd
  3. Oct 25, 2015 #2

    Simon Bridge

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    Welcome to PF;
    Is the collision of the bullet and block elastic? i.e. is kinetic energy conserved?
    Check by conservation of momentum.
     
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