A bullet goes through a ballistic pendulum, what is it's initial velocity?

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SUMMARY

The discussion centers on calculating the initial velocity of a 7.0-g bullet that passes through a 1.5-kg ballistic pendulum. The bullet exits the pendulum at a speed of 200 m/s, and the pendulum rises to a height of 12 cm. The solution involves applying the conservation of momentum principle, particularly for glancing collisions, to determine the bullet's initial speed before impact.

PREREQUISITES
  • Understanding of conservation of momentum in physics
  • Familiarity with ballistic pendulum mechanics
  • Ability to convert units to SI units
  • Knowledge of energy conservation principles
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  • Study the conservation of momentum in glancing collisions
  • Learn how to analyze ballistic pendulum problems
  • Review the conversion of units in physics calculations
  • Explore the relationship between potential energy and maximum height in pendulum motion
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Students studying physics, particularly those focusing on mechanics and momentum, as well as educators seeking to clarify concepts related to ballistic pendulums and energy conservation.

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Homework Statement


A 7.0-g bullet is fired into a 1.5-kg ballistic pendulum. The bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 12 cm. Find the initial speed of the bullet.


Homework Equations


Conservation of Momentum


The Attempt at a Solution


I first converted all of my units into SI units. I then went to use the Conservation of Momentum for Glancing Collisions, with X and Y components, but I am confused as to what the components of the bullet are. All I know is that the pendulum rises at some angle to .12 m above it's original position and I'm not sure how to interpret this into an equation. Any assistance will be greatly appreciated.
 
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Is it necessary to do this with Cons of momentum as Cons of energy seems easier?
 

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