(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A bullet shot underwater will experience "viscous drag" and follow this velocity equation.

v_{x}(t)=v_{ox}e^{-bt}

What is the maximum position of the bullet (if you were to wait a long time, what will its position be)?

Given: v_{ox}=247m/s

b=0.53 s^{-1}

x_{0}=47.9m

2. Relevant equations

x(t)=d(v_{x})/dt, v_{x}=d(a_{x})/dt

3. The attempt at a solution

I'm not sure where to start. The only thing I came up with is that when the v=0, that would be the max position although that isn't giving me the correct answer.

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# A bullet shot underwater given a velocity function

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