1. The problem statement, all variables and given/known data A bullet shot underwater will experience "viscous drag" and follow this velocity equation. vx(t)=voxe-bt What is the maximum position of the bullet (if you were to wait a long time, what will its position be)? Given: vox=247m/s b=0.53 s-1 x0=47.9m 2. Relevant equations x(t)=d(vx)/dt, vx=d(ax)/dt 3. The attempt at a solution I'm not sure where to start. The only thing I came up with is that when the v=0, that would be the max position although that isn't giving me the correct answer.