A bullet with a velocity of 575m/s Use work and energy considerations

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SUMMARY

The discussion focuses on the physics problem involving a 7.8g bullet traveling at 575m/s that penetrates a tree trunk to a depth of 5.50cm. The average frictional force stopping the bullet is calculated using work-energy principles, yielding a value of 23,400 N. For the time elapsed during penetration, the correct approach involves using impulse-momentum relationships, resulting in a time of 1.91e-4 seconds, correcting the initial miscalculation that assumed constant velocity.

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  • Understanding of kinetic energy and work-energy principles
  • Familiarity with impulse and momentum concepts
  • Basic knowledge of Newton's laws of motion
  • Ability to perform calculations involving force, mass, and velocity
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  • Learn about impulse-momentum relationships in physics
  • Explore the concept of friction and its calculations in different materials
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of work-energy and impulse-momentum applications in real-world scenarios.

sarahjt1
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Homework Statement



A 7.8g bullet moving at 575m/s penetrates a tree trunk to depth of 5.50cm. (a) Use work and energy considerations to find the average frictional force that stops the bullet. (b) Assuming that the frictional force is constant, determine hot much time elapses between the moment the bullet enters the tree and the moment it stops.

Homework Equations



I figure part (a) by:

KEi - Fk = KEf
KEi= kinestic energy initial, Fk=frictional force, and KEf= kinetic energy final

For part (b) I thought that the t=D/r would be sufficient but it's not?? I don't really understand what other equations to use in this scenario... HELP!

The Attempt at a Solution



For part (a)


1/2mV^2 - Fk*d = 1/2mVf^2
1/2(.0078)(575)^2 - .055Fk = 0
1289.44 - .055Fk = 0
-.005Fk = -1289.44
Fk = 2.34e4 N

For part (b)

t= .055/575
t= 9.5e-4 --> which is not correct, book shows 1.91e-4, huh? :cry:

Homework Statement

 
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What you are doing is assuming that the bullet travels at a constant velocity and suddenly stops after penetrating 5.50cm into the wood o.0, which definitely does not hold true especially when it is decelerating at a constant rate!
Think along the lines about the relation between impulse and force-time.
 
Ohhh... so this is a momentum question.

F delta t = mVi - mVf

so...

F delta t = (.0078)(575)- (.0078)(0)
2.34e4 (delta t)= 4.49
delta t = .000191 = 1.91e-4

Ah.. Thank you! I would have never of seen that relationship... grrr.
 

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