A car and a train colliding with each other.

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SUMMARY

The discussion focuses on the elastic collision between a car and a train, where the mass of the train is significantly larger than that of the car. The key equations used include the conservation of momentum and kinetic energy, specifically m1u1 + m2u2 = m1v1 + m2v2 and 0.5(mass of car)*v^2 + 0.5(mass of train)*V^2 = 0.5*mass of car*(v1)^2 + 0.5(mass of train)*(v2)^2. The conclusion drawn is that in such collisions, the velocity of the lighter object (the car) after impact can be approximated to be nearly equal in magnitude but opposite in direction to its initial velocity, due to the large mass difference. This principle is analogous to a rubber ball colliding with a brick wall.

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Homework Statement



A car and a train collides with each other in an elastic collision. The mass of the train is much more larger than the mass of the car. Ignore air resistance and friction from the railway tracks and roads.
Just before impact the car has a velocity of (V) train has a velocity of (-V).

What is the velocity of the car immediately after its collision with the train? Express your answer in terms of (V).

Homework Equations


m1u1+m2u2=m1v1+m2v2
0.5(mass of car)*v^2 + 0.5(mass of train)*V^2= 0.5*mass of car*(v1)^2 + 0.5(mass of train)*(v2)^2

The Attempt at a Solution


i tried using:
m1u1+m2u2=m1v1+m2v2
as well as conservation of K.E as the collision is elastic.
but there seem to be too many unknowns and i can't express my answer in terms of just (V)..
 
Last edited:
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Mtrain >>> Mcar. So, the initial and final momentum of the train will be approximately equal.

Do you, by any chance, remember a special approximation for an object of very small mass colliding with an object of very large mass?

Think about kicking a rubber ball directly at a brick wall. The speed of the ball will be about the same before and after hitting the wall, but in the opposite direction. This works here as well, but you need to choose a frame of reference in which the train is motionless to get the right result.
 

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